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GCSE Past Paper Questions & Solutions
Dr J Frost Last modified: 18th April 2014
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Index More Topics >> Click to visit section.
Straight Line Equations Algebra Factorising, Simplifying & Solving Non-Right Angled Triangles Congruent Triangle Proofs Algebraic Proofs & Algebraic Geometry Right-Angled Triangles Number Includes bounds, direct/indirect proportion, standard form, %s, etc. Probability Circle Theorems Volumes and Surface Area Functions and Graph Transformations More Topics >> Mark Scheme Notes: M1 Method mark. cao Correct Answer Only oe Or equivalent A1 Accuracy mark. C ‘Communication Mark’ (used for *-ed questions) B1 ‘Independent mark’. Sort of a ‘miscellaneous’ mark, often used when an explanation is required.
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Index Click to visit section. Vectors Loci & Constructions
Angles & Bearings Mark Scheme Notes: M1 Method mark. cao Correct Answer Only oe Or equivalent A1 Accuracy mark. C ‘Communication Mark’ (used for *-ed questions) B1 ‘Independent mark’. Sort of a ‘miscellaneous’ mark, often used when an explanation is required.
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<< Return to Index
Straight Lines << Return to Index Gradient = -9/4 ? 2y = -x + 1, so y = -0.5x + 0.5 So gradient is -0.5 ? y = 3x - 4 ? ? y = -3x + 16 ? y = 4x + 3 y = 4x – 5 ?
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Straight Lines << Return to Index y = 4x - 11 ? y = (1/3)x + 2 ? y = -(1/2)x + c (where c can be anything) ? y = -(1/5)x – 1 ?
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Straight Lines << Return to Index 4. Finding where a line intercepts the 𝒙 or 𝒚 axis. At what point does 𝑦=2𝑥+3 intercept: The 𝑦-axis: (𝟎,𝟑) The 𝑥-axis: 𝟎=𝟐𝒙+𝟑 𝒔𝒐 𝒙=− 𝟑 𝟐 → − 𝟑 𝟐 ,𝟎 At what point does 𝑦=3𝑥−2 intercept: The 𝑦-axis: 𝟎,−𝟐 The 𝑥-axis: 𝟐 𝟑 ,𝟎 ? ? ? ? 5. Sketching a line with a given equation. Sketch the line 𝑦=2𝑥−4 between 𝑥=−1 and 𝑥=3 6 4 2 -2 -4 -6 Tips: Be careful about the axis. You only need to plot two points. E.g. use 𝑥=−1 and 𝑥=3, work out the 𝑦 values for these, then join the two points with a line. Reveal
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Straight Lines << Return to Index ?
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Straight Lines << Return to Index ?
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Straight Lines << Return to Index ? , -9/5 ?
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Straight Lines << Return to Index Reveal ? 5 1.5
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Straight Lines << Return to Index Reveal
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Straight Lines << Return to Index 2/3 ? Gradient of 2y = 10 – 3x is -3/2 2/3 × -3/2 = -1 therefore perpendicular ?
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Straight Lines << Return to Index ? 6 ? 1.5 ? Reveal -3/2 ?
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Straight Lines << Return to Index ? -0.6, 5.5 ? -1.4, 6.4 x = 0.2, y = -3.8 x = 5.8, y = 1.8 ?
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Straight Lines << Return to Index ? y = -(1/2)x – 1 -1/2 ?
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Straight Lines << Return to Index [June 2010 NonCalc]
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Algebra << Return to Index ?
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Algebra << Return to Index x10 ? m12 ? ?
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Algebra << Return to Index ? ?
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Algebra << Return to Index 3 ? -1 ?
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Algebra << Return to Index 12.5 ? 4m2 – 1 ?
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Algebra << Return to Index ?
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Algebra << Return to Index a9 ? 9e5f6 ? 3 ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index 3(2 + 3x) ? (y + 4)(y – 4) ? (2p – 5)(p + 2) ?
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Algebra << Return to Index -3 ?
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Algebra << Return to Index 4 ? ? 5 4 , 5 ?
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Algebra << Return to Index ? ?
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Algebra << Return to Index ? ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index ? -3 < x ≤ 4 ? t > 7/2 ?
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Algebra << Return to Index 2x(x – 2y) ? (p – 4)(p – 2) ? x + 2 ? 6a5b2 ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index x + 4 2x – 3 ? 7x – 2 (x+2)(x-2) ?
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Algebra << Return to Index (x + p)(x + q) ? (m + 2)(m – 2) ? x + 10 (x – 4)(x + 3) ?
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Algebra << Return to Index x2 + 3 = 7x x2 – 7x + 3 = 0 x = (7 ±37) / 2 ?
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Algebra << Return to Index -2, -1, 0, 1, 2, 3, 4 ? x > 5/2 ?
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Algebra << Return to Index ? 16n12
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Algebra << Return to Index (2x – 1)(x – 4) ? ? (2x – 1)(x – 4) = (2x – 1)2 x – 4 = 2x – 1 x = -3
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Algebra << Return to Index -160 ? ?
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Algebra << Return to Index 4(3n + 1) ? 3(n + 4) ? 2n + 1 ?
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Algebra << Return to Index ?
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Algebra << Return to Index ?
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Algebra << Return to Index 4x-1 or 4/x ?
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Algebra << Return to Index 8x2 + 6xy – 20y2 ? x + 10 ? x – 5 x + 2 ? 3 -11 ? ?
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Algebra << Return to Index ?
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Non-Right Angled Triangles << Return to Index ?
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Non-Right Angled Triangles << Return to Index ?
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Non-Right Angled Triangles
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Non-Right Angled Triangles
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Congruent Triangles << Return to Index ?
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Congruent Triangles ? ?
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Congruent Triangles ?
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Congruent Triangles ?
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Algebraic Proofs and Geometry << Return to Index 21. ?
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Algebraic Proofs and Geometry << Return to Index ? 5x2
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Right Angled Triangles << Return to Index ?
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Right Angled Triangles << Return to Index ? 80.1
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Right Angled Triangles << Return to Index ? ? 11.5 47.2
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Right Angled Triangles << Return to Index ?
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Right Angled Triangles << Return to Index ? 3.52
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Right Angled Triangles << Return to Index ? ? 33.7 9.44
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Right Angled Triangles << Return to Index ? 13.86
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Right Angled Triangles << Return to Index ? 48.2
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Number << Return to Index ? 9.56 x 107 ? ?
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Number << Return to Index ?
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Number << Return to Index ? Remember, you choose the greatest degree of accuracy such that the two bounds are the same.
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Number << Return to Index ? ? 3.76 x 10-4 ? 0.5 x 109 = 5 x 108
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Number << Return to Index Non ?
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Number << Return to Index Non ?
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Number << Return to Index ? ? 16 x 10-5 = 1.6 x 10-4
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Number << Return to Index 1 ? ? 2.7 x 1014 ? 2.4 x 1016 ? 6.4 x 108 ?
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Number << Return to Index 8.25 x 107 ? 1.456 x 10-15 ?
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Probability << Return to Index ?
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Probability << Return to Index ?
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Probability << Return to Index ?
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Probability << Return to Index ? 2 42 ? 16 42
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Probability << Return to Index ? 222 380
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Probability << Return to Index ? ? 64 110
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Probability << Return to Index ?
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Probability << Return to Index ?
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Circle Theorems << Return to Index ?
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Circle Theorems << Return to Index ?
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Circle Theorems << Return to Index ?
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Circle Theorems << Return to Index
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Circle Theorems << Return to Index ?
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Circle Theorems << Return to Index ? Angle DAB = 180 – 103 = 77 (opposite angles of cyclic quadrilateral) Angle DBA = 39 (Alternate Segment Theorem) Angle ADB = 180 – 77 – 39 = 64
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Circle Theorems << Return to Index ? 116 ? Angle OCB = (180 – 116)/2 = 32 Angle OCA = 74 – 32 = 42
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Circle Theorems << Return to Index ? Angle BOA = 152 Angle APB = 360 – 152 – 90 – 90 = 28
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Volumes and Surface Area << Return to Index ?
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Volumes and Surface Area << Return to Index ? 236 ?
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Volumes and Surface Area << Return to Index ? ? 4 ? 3 2 ? 1
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Volumes and Surface Area << Return to Index ? ?
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Volumes and Surface Area << Return to Index ? Yes Yes ? 8 x 1003 =
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On to questions >>>
Functions and Graph Transformations << Return to Index General Tips: When asked to sketch a transformed graph, e.g. f(x + 3), pick key points on the original graph to transform first (e.g. ones that go exactly through grid points, or y-intercepts, etc.) then join up with a line. This will ensure you draw it accurately. Remember that changes inside the function brackets affect the x-axis and do the opposite of what you expect. Learn the shape of y = sin(x), y = cos(x) and y = tan(x). In particular, learn that coordinates for which the graphs cross the x-axis, and the maximum/minimum points. On to questions >>>
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Functions and Graph Transformations << Return to Index Reveal To get the curve perfectly mirrored, mirror points that go through squares first, i.e. (-4, 4), (-3, 1), (-1, 1), (0.4), then join up with a line.
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Functions and Graph Transformations << Return to Index ? y = f(x – 6)
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Functions and Graph Transformations << Return to Index ? Reveal
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index E B F C D A ?
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index Reveal
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Functions and Graph Transformations << Return to Index ? ? ? ? Reveal
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Functions and Graph Transformations << Return to Index Reveal ? x = -1.6, y = 2.6 x = 2.6, -1.6
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Functions and Graph Transformations << Return to Index ? f(x – 5) ?
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? ? ? Reveal
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Vectors << Return to Index ? ?
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Loci & Constructions << Return to Index #1: Use compass the get some fixed distance across the lines AC and AB. Reveal #2: Find perpendicular bisector of these two points.
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Loci & Constructions << Return to Index Reveal
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Loci & Constructions << Return to Index Reveal Step #1 #1: Use two arcs with radius the width of the line to form an equilateral triangle (only one side needed). This gives you an angle of 60. Reveal Step #2 #2: Find the angle bisector of these two lines in the usual way, in order to find the angle half of 60.
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Loci & Constructions << Return to Index ?
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Loci & Constructions << Return to Index Reveal Angle bisector of angle DAB 5cm 3cm
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Angles & Bearings << Return to Index 40 ? Angle PQT = 70 (angles on straight line add to 180). Angle PTQ = 70 (base angles of isosceles triangle are equal) Angle TPQ = 40 (angles in triangle add to 180) ?
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Angles & Bearings << Return to Index ? 360 ÷ 5 = 72
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Angles & Bearings << Return to Index 112 ? ?
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Angles & Bearings << Return to Index 55 ? ? Corresponding angles.
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Angles & Bearings << Return to Index 360 ÷ 30 = 12 ?
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Angles & Bearings << Return to Index 360 – 90 – 120 = 150 ?
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Angles & Bearings << Return to Index 42 ?
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Angles & Bearings << Return to Index Angle PBA = 180 – (x + 50) – (2x – 10) = 140 – 3x y = 180 – (140 – 3x) = 3x + 40 ? ? 3x + 40 = 145 x = 35 ? = 85
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Angles & Bearings << Return to Index ? 3x – 15 = 2x + 24 x = 39
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Angles & Bearings << Return to Index ? Interior angle of hexagon = 180 – (360 / 6) = 120 Interior angle of octagon = 180 – (360 / 8) = 135 x = 360 – 120 – 135 = 105
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Angles & Bearings << Return to Index ? 150 ?
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