1. Temperature and Volume Relationship of Gases (Charles’s Law) Temperature and Pressure Relationship of Gases (Gay Lussac’s Law)
A.10/A.11 In text

2. Using the data you gathered in investigation A.9 fill in the table:
Based on A.9 and A.1 investigations: what is the relationship between Temperature and Volume in gases?
Temp (oC)
Volume
(in mm)
90o
8.5mm
80o
7.9mm
70o
7.3mm

3. A.1 Investigation 2: Balloons in Water of Differing Temperatures
What happened to the volume of the balloon in hot water:
What happened to the volume of the balloon in ice water:

5. Summarize the relationship between pressure and volume for a gas at a constant temperature.
What is the quantitative way to summarize this relationship? (the mathematical formula?)

6. When pressure and amount of gas molecules is held constant:
As temperature goes up volume goes up
As temperature goes down, volume goes down
DIRECT
RELATIONSHIP

7. **Unit for temperature MUST be in KELVINS!
Charles’ Law:

8. What about the relationship between temperature and pressure at a constant volume? (Gay-Lussac’s Law)
Temperature must still be in units of Kelvin!
Direct relationship

9. Problem #1
Temperature will affect airships in Tyria – a fantasy world. The small airships have an initial volume of 4,200L. To replicate atmospheric conditions in Tyria scientists place it in a chamber and reduce the temperature from 20 to -60oC. What will the final volume of the airship be?

10. Steps to Solve :
First predict how the change will affect the volume (will it go up or down)?
Second: Convert any temperatures to Kelvin (oC + 273)
Third: define each variable (should be 1 unknown)
V1: T1: V2: T2:
Fourth: “Plug” the values into the equation

11. Problem #1:

12. 4200L = V2 -> (4200L) * (213K) = V2 293K 213K (293K) V2 = 3100L
First predict how the change will affect the volume (will it go up or down)? If the temperature goes down the volume should be smaller than 4,200L.
Second: Convert any temperatures to Kelvin
(oC + 273)
T1: = 293 K, T2: = 213 K
V1: 4200L T1: 293K V2: ? T2: 213K
Fourth: “Plug” the values into the equation. (Cross multiply)
4200L = V2 -> (4200L) * (213K) = V2
293K K (293K)
V2 = 3100L

13. When problem has been checked off: 1. Complete A. 11 1-4 AND A
When problem has been checked off: 1. Complete A AND A.11 Extra Practice Concept Check All are due next class meeting