1. SA3202, Solution for Tutorial 2
Day Mon Tue Wed Thu Fri Sat Sun Total
# of Suicide
Expected
H0: p1=p2=p3=p4=p5, p6=p7 (1 free parameter p1 while p6=(1-5*p1)/2 is not free )
T= , G= , df=7-1-1=5, 95% table= H0 is rejected.
H0: p1=31/365, p2=28/365,…,p11=30/365, p12=31/365.
(no free parameter)
T=56.76, G=57.35, df=12-1-0= % table= Reject H0.
11/14/2018
SA3202, Solution for Tutorial 2

2. SA3202, Solution for Tutorial 2
3. For the Number of Boys Data, assume that the number of boys following a binomial distribution with probability ½: That is,
H0: p0=1/16, p1=4/16, p2=6/16, p3=4/16,p4=1/16 (no parameter is free)
T=14.26, df=5-1-0=4, 95% table=9.488, 90% table= Reject H0.
Assume that the number of boys following a binomial distribution with unknown success probability theta. (1 free parameter theta)
The theta is estimated as
T= Df=5-1-1=3, 90%table=6.25, 95%table=7.81. Do not eject H0. More boys were born.
4. For the Political View Data, assume that the political views are symmetric:
H0: p1=p7, p2=p6, p3=p5. (3 free parameters, p1,p2,p3 while p4=1-2(p1+p2+p3) is not free)
T=7.078, df=7-1-3=3, 90%table=6.25, 95%table=7.81. Do not eject H0 when alpha=5%.
For the Number of Boys Data, assume symmetry:
H0: p0=p4,p1=p3 (2 free parameters p0, p1 while p2 =1-2(p0+p1) is not free) Oi Ei
T= , G= , df=5-1-2=2 , 95% table= Reject H0.
The number of boys is not symmetric.
11/14/2018
SA3202, Solution for Tutorial 2