1. Practice Quiz 3
Hurley

2. For the quiz …
I will provide you with a categorical proposition, like…
No apples sold in Minnesota are mushy weapons
I’ll ask you for its
quality
qualifier
quantity
quantifier
copula
distribution
letter name
terms

3. 1 Consider: No non-A are B (T) Obversion Some non-A are B. (F)
All A are non-B. (Und.)
All non-A are non-B. (T)
Some non-A are not B. (T)
No B are non-A. (T)

4. 2 Consider: All A are non-B. (F) Contraposition All A are non-B. (F)
All non-B are A. (Und.)
No non-A are B. (Und.)
All B are non-A. (F)
Some non-A are not B. (T)

5. 3 Consider: Some A are not non-B. (T)  Some A are B.
Contraposition (T)
Contrary (F)
Conversion (T)
Obversion (T)
Subcontrary (Und.)

6. 4 Consider: Some non-A are B. (F)  Some B are non-A. Subcontrary (T)
Conversion (Und.)
Contraposition (Und.)
Conversion (F)
Contraposition (F)

7. 5 Assume Aristotle (Traditional standpoint). Consider:
Some A are non-B. (F)  Some A are not non-B. (F)
Illicit, contrary
Illicit, subalternation
Subcontrary
Illicit, subcontrary
Contraposition

8. 6 No S are P. (Aristotelian standpoint) After filling in the diagram …
Area 2 is shaded, and there is a circled X in area 1.
Areas 1 and 3 are shaded.
Area 1 is shaded, and there is a circled X in area 2.
There is an X in area 2.
Area 1 is shaded, and there are no other marks.

9. 7 All S are P. (Boolean standpoint) After filling in the diagram …
Areas 1 and 3 are shaded.
Area 2 is shaded, and there are no other marks.
Area 1 is shaded, and there is a circled X in area 2.
There is an X in area 2.
Area 1 is shaded, and there are no other marks.

10. 8 Shade area 2 and place an X in area 1.
Which of the following would be valid inferences:
shaded area 2.
an X in area 3.
an X in area 1.
shaded 1.
no X’s or shadings.

11. 9 Shade area 1 and place an X in area 2.
Which of the following would be valid inferences:
shaded area 2.
an X in area 3.
shaded area 1, and X in area 2.
shaded 1.
no X’s or shadings.

12. 10 Assume Aristotle (Traditional standpoint). Consider:
No non-A are B. (T)  Some non-A are not B. (F)
Illicit, subalternation
Illicit, contradictory
Contradictory
Illicit, subcontrary
Conversion

13. 11 Assume Bool (Modern standpoint). Consider:
No A are B. (T)  Some A are B. (F)
Existential fallacy
Illicit, contradictory
Contradictory
Illicit, subcontrary
Conversion

14. 12 Assume Bool (Modern standpoint). Consider:
No A are B. (T)  All A are B. (F)
Existential fallacy
Illicit, contrary
Contradictory
Illicit, subcontrary
Conversion

15. 13 Assume Aristotle (Traditional standpoint)
All square circles are happy shapes.
 Some square circles are happy shapes.
Existential fallacy
Valid, contradictory
Valid, subcontrary
Invalid, subalternation
Invalid, contrary