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Solve Linear and Quadratic Systems Algebraically

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Presentation on theme: "Solve Linear and Quadratic Systems Algebraically"— Presentation transcript:

1 Solve Linear and Quadratic Systems Algebraically
Remember solving SYSTEMS of LINEAR equations you could do it graphically, or algebraically using substitution or elimination (A.K.A. linear combinations). Try this: Consider the linear system: y = 2x + 5 x + 2y = 15 . Solve the linear system using substitution. b. Explain what that ordered pair represents. SUBSTITUTION was used because it is the only method we can use to solve linear-quadratic systems algebraically. Because we are dealing with quadratic equations, it is natural to expect more than one answer. Think about this: Consider the sketch of a line and a parabola. a. What is the maximum number of intersection points that a line and a parabola could have? Illustrate with a picture. b. What is the minimum number of intersection points c. Is it possible for a line and a parabola to intersect in only one point? If so, illustrate with a picture.

2 Use a graphing calculator to solve the system below. Use the “Calculate Intersection” and “Table” features. Find a good window where you can see both equations and their intersection points clearly. Draw a picture of your screen and state the window you used. y = x2 + 2x – 6 3x + y = -12 Xmin= Xmax= Xscl= Ymin= Ymax= Yscl=


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