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Class Notes 11: Power Series (3/3) Series Solution Singular Point

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Presentation on theme: "Class Notes 11: Power Series (3/3) Series Solution Singular Point"— Presentation transcript:

1 Class Notes 11: Power Series (3/3) Series Solution Singular Point
182A – Engineering Mathematics

2 Series Solution Ordinary & Singular Point
Ordinary Point (OP) Singular Point (SP) Regular Singular Point (RSP) Irregular Singular Point (ISP)

3 Series Solution about Ordinary Point (OP)
Definition Solution (Typically 2) Example

4 Series Solution about Regular Singular Point (RSP)
Definition Solution (Typically 2) Example

5 RSP - Second solution Assume case 1, 2; case 3 Case 1 If are distinct
is positive non integer Case 2 If are distinct is a positive integer constant that can be zero

6 RSP - Second solution (Continue)
Case 3

7 Series Solution about Non Regular Singular Point (NSP)
Definition

8 Classification of Singular Points – Example
which type of singular point (Regular/Irregular)

9 Classification of Singular Points – Example
For x0=2 Factor (x-2) Both functions are analytic at x=0 Regular Singular Point (RSP) For x0=-2 Factor (x-(-2)) =x+2 Non-analytic at x0=-2 Irregular Singular Point (IRS)

10 Frobenius’ Theorem If x= x0 is a regular singular point of the differential equation Then there exists at least one solution of the form where the number r is a constant to be determined. The series will converge at least at some interval

11 Solution Protocol Substitute into the given differential equation
Determine the unknown coefficients cn using reduction relations Find the unknown exponent r. (non-negative integer) For the sake of simplicity in solving the differential equation, the regular singular point is x0=0 for any other regular singular point x0

12 RSP (Case 1) - Example (Two Series Solutions)
What type of point x0=0 is of the ideational equation? Regular Point (RP) Regular Singular Point (RSP) Irregular Singular Point (IRS) Conclusion - Regular Singular Point (RSP)

13 RSP (Case 1) - Example (Two Series Solutions)
Assuming a solution of the form Plug the solution into the differential equation

14 RSP (Case 1) - Example (Two Series Solutions)

15 RSP (Case 1) - Example (Two Series Solutions)
Because nothing is gained by taking c0=0, we must then have (*) Plugging r1, r2 into (*) (o) (+) Case 1 – Positive Non-Integer

16 RSP (Case 1) - Example (Two Series Solutions)
For (r1=2/3) Eq (o) For (r2=0) Eq (+) We encounter something that didn’t happen when we obtained solutions about an ordinary point. The two sets of coefficients contains the same multiple c0. We can omit the term c0

17 RSP (Case 1) - Example (Two Series Solutions)
Using the ratio test both y1(x) and y2(x) converge for all values of x (except the origin) y1(x) and y2(x) are linearly independent for all

18 RSP - Indicial Equation
Indicial roots or exponents The indicial equation is typically quadratic equation It is possible to obtain the indicial equation in advance of substituting into the diff. eq. of the singularity

19 RSP - Indicial Equation
Obtain the indicial equation in advance of substituting into the diff. eq. If x = 0 is a regular singular point of Than are analytic at x = 0 - That is the power series expansions are valid or intervals that have a positive radius at convergence

20 RSP - Indicial Equation
- By multiplying by we get After substituting and the two series for we find that the general indicial equation to be where are defined by

21 RSP (Case 2)- Example Indicial Equation (Direct Derivation)
The indicial equation is Case 2 – Positive Integer

22 RSP (Case 2) - Example (only one series solution)

23 RSP (Case 2) - Example (only one series solution)

24 RSP (Case 2) - Example (only one series solution)

25 RSP (Case 2) - Second Solution
Finding a second solution ( positive integer case II) We may or may not be able to find a second solution depends on Indicial roots Recurrence relation of c may be equal to 0 if We may use the following term for the second solution

26 RSP (Case 2) - Second Solution
Construct a second solution using the formula

27 Example (Finding a second solution)


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