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1 Dozen Eggs = ________eggs. 1 Ream of Paper = _______ sheets of paper.
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If you think I’m Wait till you watch this…
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mole and is abbreviated mol.
The Mole Scientists needed a unit to bridge between the invisible world of atoms and macroscopic world of materials and objects. This unit is called a mole and is abbreviated mol. A mole is a fundamental SI unit used to measure the amount of a substance.
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A mole IS A COLLECTION OF 6.02 x 1023 PARTICLES
Particles can include: Atoms Molecules Compounds
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Why use the mole? The mole is used because there is exactly 1 mole of atoms in the atomic mass of an element when that mass is expressed in grams. Molar mass for all purposes is the same as the atomic mass. So 1 mole of C-12 , or 6.02 x 1023 atoms, has a mass of g.
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Who is Avogadro? The number is named after Amedeo Avogadro because his ideas were crucial to the early development of chemistry.
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Practice finding molar mass!
1 mole of any element is equivalent to it’s molar mass. H = g = 1 mole O2 = 16.0 x 2 = 32.0 g = 1 mole H2SO4 = g = 1 mole
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How many moles are in 90.0 g of water?
Formula of water: H2O Molar mass of water: g = 1 mole Equation: g x 1 mole = moles 18 g Answer: 5 moles
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How many grams are in 6.1 moles of NaCl?
Molar mass: 1 Na x g = 1 Cl x g = Equation: 6 moles NaCl x gNaCl = grams 1 mol NaCl Answer with Sig Figs: 360 grams NaCl
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How many grams are in 0.251 moles of HF?
Molar mass: 1 H x g = 1 F x g = Equation: 0.251 moles HF x g HF = grams 1 mol HF Answer with Sig Figs: 5.02 g HF
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How many molecules are in 0.25 moles of water?
Formula of water: H2O Conversion factors needed: 1 mole H2O = 18 g H2O & 1 mole = 6.02 x 1023 particles Equation: 0.25 moles H2O x x 1023 particles = 1 mol H2O Answer with sig figs: 1.5 x 1023 particles H2O
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How many moles are in 5.23 x 1020 molecules of MgS?
Conversion factor needed: 1 mole = 6.02 x 1023 particles Equation: 5.23 x 1020 part MgS x mole MgS = 6.02 x 1023 part MgS Answer with Sig Figs = mol MgS
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How many molecules are in 10.0 g of NF3?
Molar mass: 71.0 g Equations: 10.0 g NF3 x mole NF3 x x 1023 part NF3 71.0 g NF mole NF3 Answer with sig figs: x 1022 part NF3
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How many grams does 1.80 X 1024 molecules of Cu(OH)2 weigh?
Molar Mass: g Equations: 1.80 X 1024 part Cu(OH)2 x mole Cu(OH) x g Cu(OH)2 6.02 x 1023 part Cu(OH) mol Cu(OH)2 Answer with sig figs: g Cu(OH)2
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