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Standard Deviation Example
Example taken from the following website
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A vet measures the height of 5 dogs....
The heights (at the shoulders) are: 600mm, 470mm, 170mm, 430mm and 300mm.
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Find the standard deviation of the dog heights
First find the mean (μ)
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Now subtract the mean from each dog height (x - μ)
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Next, take each of the differences just found and square them
(206)2 = 42436 (76)2 = 5776 (-224)2 = 50176 (36)2 = 1296 (-94)2 = 8836
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Σ(x - μ)2 Now, find the sum of all those squared numbers
=
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This number is called the variance.
Take that sum number and divide by how many numbers you have. Σ(x - μ)2 n 108520 = 21,704 5 This number is called the variance. σ2
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√ √ Finally, take the square root of the variance Σ(x - μ)2 n 21,704
147.3 This number is the standard deviation σ
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The standard deviation shows which dogs fall under “normal” height and which dogs are too tall or too short.
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