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Chapter 5 Quadratic Functions
5.1 Graphing Quadratic Functions
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Objectives Graph quadratic functions Assignment: odd
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Definitions Quadratic Equation: has the form of y=ax2+bx+c and its graph is U-shaped and called a parabola. The lowest or highest point on the graph of a quadratic equation is the vertex. The axis of symmetry for the graph of a quadratic equation is the vertical line through the vertex.
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(0,-3) (0,0) (0,2)
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(3,0) (1,0) (-2,0)
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(2,1) (2,-3)
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A quadratic functions has the form:
We call it’s shape a parabola. The vertex is the “lowest” (or “highest”) point on the parabola. The axis of symmetry is a vertical line through the vertex.
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The graph of is a parabola with these attributes: The parabola opens “upward” if a > 0. The parabola opens “downward” if a < 0. The parabola gets “wider” as a gets smaller. RULES TO MEMORIZE!! The parabola gets “narrower” as a get bigger. The x-coordinate of the vertex is The axis of symmetry is the vertical line
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Find and plot the vertex:
Graph: Solution: Note that the coefficients for this function are a = 2, b = -8, c = 6. Since a > 0, the parabola opens up. Find and plot the vertex: (-) The vertex has coordinates (2,-2) Draw the axis of symmetry x=2 Plot a couple of points on one side of the axes of symmetry, such as (1,0) and (0,6). Use symmetry to plot two more points, such as (3,0) and (4,6)…….
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The quadratic function
is written in standard form. Two other useful forms for quadratic functions are given below: Vertex and Intercept forms of a Quadratic Functions Form of Quadratic Function Characteristics of Graph The vertex is (h,k) Vertex Form: The axis of symmetry is x = h. Intercept Form: The x-intercepts are p and q. The axis of symmetry is half way between (p,0) and (q,0) For both forms, the parabola opens up if a > 0 and down if a < 0.
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Graph this equation given in Vertex Form:
Solution: The vertex is (-3,4). The parabola opens down since a < 0. The axis of symmetry is the vertical line x = -3. Plot two points, say (-1,2) and (-5,2).
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Graph this quadratic function given in Intercept Form.
y = -(x + 2)(x - 4) Solution: The x-intercepts are –2 and 4. The axis of symmetry is x = 1. (WHY?) The vertex has coordinates (1, 9). (WHY?)
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You can change quadratic functions from intercept form to standard form by multiplying the algebraic expression. (x + 3)(x + 5) = + 5x +3x +15
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Does the parabola open up or down?
Is the last equation in standard form?
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