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Eureka MATH 2017 September 11 to 15
Do Now Week #6 Eureka MATH 2017 September 11 to 15
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IWBAT determine that a scale drawing is either the reduction or the enlargement of a two-dimensional picture BTEOC. September 11,2017 Do Now #1 September 11,2017 Do Now #2 Multiply each fraction and cross cancel to simplify. Write your answer as a mixed fraction ∙ 5 11 = or ∙ 7 5 = or Multiply each fraction and cross cancel to simplify. Write your answer as a mixed fraction. 4 5 ÷ 4 16 = 16 5 or ÷ 7 3 = 8 7 or 1 1 7
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IWBAT recognize the scale factor to be the constant of proportionality.
September 12, 2017 Do Now#1 September 12, 2017 Do Now#2 Use a scale factor to find the missing side of the scalene triangle. Use a scale factor to find the missing side of the quadrilateral. x is to 4 as 15 is to 20 x 4 = /5 = 4 and 15/5 = 3 so x = 3 x is to 10 as 24 is to 60 x 10 = /6 = 10 and 24/6 = 4 so x = 4
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Given a scale drawing, IWBAT compute the lengths in the actual picture using the scale BTEOC.
September 13, 2017 Do Now #1 September 13, 2017 Do Now #2 A model train has a scale of 1 in : 3 ft. If the model train is 7 in tall, then how tall is the real train? 1 in. is to 3 ft. as 7in are to 21 ft. 1𝑖𝑛 3ft = 7𝑖𝑛 21ft A model rocket has a scale of 1 in : 8 ft. If the model rocket is 10 in tall, then how tall is the real rocket? 1 in. is to 8 ft. as 10 in are to 80 ft. 1𝑖𝑛 8ft = 10𝑖𝑛 80ft
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Given a scale drawing, IWBAT compute the area in the actual picture.
September 14, 2017 Do Now #2 September 14, 2017 Do Now #1 Sketch the rectangle to determine the scale factor and find the missing side. Bonus: Calculate the area of each figure. Sketch the rectangle to determine the scale factor and find the missing side. Bonus: Calculate the area of each figure. x is to 12 as 18 is to 6 x 12 = 18 6 X = 18 x 2 or 36 units since 6 x 2 = 12 X is to 7 and 96 is to 42 x 7 = 96 42 42 ÷ 6 = 7 and 96 ÷ 6 = 16 so x = 16
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IWBAT complete a scale factor quiz on lessons 16-19 with 80% accuracy BTEOC.
September 15, 2017 Do Now #1 September 15, 2017 Do Now #2 Stockton and Seattle are 14 in apart on a map that has a scale of I in : 55 mi. How far apart are the real cities? 1in is to 55 mi as 14 in is to x mi 1in 55𝑚𝑖 = 14in x 𝑚𝑖 X = 55 x 14 or 770 miles San Francisco and New York are 36 in aprart on a map that has a scale of 1 in : 81 mi. How far apart are the real cities? 81 x 36 = 2,916 miles
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