2. Final Jeopardy
Predict the products and Balance the equation for the following reaction… Mg + AlPO4 

3. BCR How to predict products for a Single Replacement Reaction
Identify what type of reaction
Balance an equation
Explain why it happens

4. Counting
Naming
Balancing
Activity
Series
Reactions
100
100
100
100
100
200
200
200
200
200
300
300
300
300
300
400
400
400
400
400
500
500
500
500
500

5. This is the number of oxygen atoms in Ca3(PO4)2.
$100
This is the number of oxygen atoms in Ca3(PO4)2. 8

6. This is the number of oxygen atoms in 2Mg(OH)2.
$200
This is the number of oxygen atoms in 2Mg(OH)2. 4

7. This is the charge for iron in FeO. A. +1 B. -1 C. +2 D. -2
$300
This is the charge for iron in FeO. A B C D. -2 C

8. $400
This is the charge that forms when chlorine gains one electron. A B C D E. 8 F. 0 B

9. $500
This is the charge on an ionic compound. A. Zero B. Depends on the ions involved C. Depends on the polyatomic ion D. You need more information A

10. Al2S3 a. Aluminum(III) sulfide b. Dialuminum trisulfide
$100
Al2S3
a. Aluminum(III) sulfide
b. Dialuminum trisulfide
c. Aluminum sulfate
d. Aluminum sulfide D

11. $200
CCl4 a. Carbon chloride b. Carbon chlorate c. Carbon tetrachloride d. tetracarbon chloride C

12. $300
Magnesium hydroxide
MgO
MgH2
MgOH2
Mg(OH)2 D

13. Cobalt(II) phosphate a. CoPO4 b. Co3(PO4)2 c. Co2(PO4)3 d. Co3P2
$400
Cobalt(II) phosphate a. CoPO4 b. Co3(PO4)2 c. Co2(PO4)3 d. Co3P2 B

14. Aluminum chloride a. Al2Cl3 b. AlCl3 c. AlCl2 d. AlCl
$500
Aluminum chloride a. Al2Cl3 b. AlCl3 c. AlCl2 d. AlCl B

15. $100
Chemical equations must be balanced because we cannot violate… a. Dalton’s Atomic Theory b. the Law of Multiple Proportions c. the Law of Conservation of Mass d. Pauli’s Exclusion Principle C

16. $200
This is the coefficient for oxygen when this equation is balanced. H2O2(aq)  H2(g) + O2(g) 1

17. $300
Potassium chloride reacts with fluorine to produce potassium fluoride and chlorine. This is the skeletal equation. a. KCl + F  KF + Cl b. KCl2 + F2  KF2 + Cl c. KCl + F2  KF + Cl2 d. K2Cl + F2  K2F + Cl e. K(Cl2)2 + F2  K(F2)2 + Cl2 C

18. $400
This is the ionic compound formed from Ag+ and SO42- a. Ag2SO4 b. AgSO4 c. Ag(SO4)2 d. Ag4(SO)2 A

19. $500
This does not belong to the group. A. chlorine B. fluorine C. sulfur D. oxygen E. hydrogen C

20. $100
This is one product formed when aluminum chloride and magnesium react. A. MgCl3 B. MgCl C. AlCl D. MgCl2 D

21. $200
This is one product formed when zinc oxide and magnesium react. A. MgO B. MgO2 C. Mg2O D. ZnMg E. MgZn A

22. $300
This is the metal(s) that barium would be able to replace. A. Li, K B. Ca, Na, Mg C. Li, K, Ca, Na, Mg D. Nothing
Lithium
Potassium
Barium
Calcium
Sodium
Magnesium B

23. $400
This is the metal that would replace barium but not lithium. A. potassium B. calcium C. sodium D. magnesium
Lithium
Potassium
Barium
Calcium
Sodium
Magnesium A

24. $500
Zn + 2HCl  ZnCl2 + H2 This explains why the above reaction is able to take place. A. Hydrogen is more reactive than zinc B. Zinc is more reactive than hydrogen C. Chlorine is more reactive than zinc D. Chlorine is more reactive than hydrogen B

25. $100
2Na + Cl2  2NaCl a. Combination b. Decomposition c. Single Replacement d. Double Replacement e. Combustion A

26. $200
Ca(OH)2 + (NH4)3PO4 a. Combination b. Decomposition c. Single Replacement d. Double Replacement e. Combustion D

27. $500
A reaction with only 1 reactant a. Combination b. Decomposition c. Single Replacement d. Double Replacement e. Combustion B

28. $300
C4H10 + O2  a. Combination b. Decomposition c. Single Replacement d. Double Replacement e. Combustion E

29. $400
 H2O + CO2 a. Combination b. Decomposition c. Single Replacement d. Double Replacement e. Combustion E