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Review of Acids.

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Presentation on theme: "Review of Acids."— Presentation transcript:

1 Review of Acids

2 HCl Strong Acid HCl  H+ + Cl-
0.10 M 0.10 M pH = -Log[H+] = No ICE HF Weak Acid HF ⇌ H F- I 0.10 M 0 0 C x x x E x x x small Ka x2 = 3.5 x x = M 0.10 pH = -Log[ ] = 2.23

3 NaOH Strong Base NaOH  Na+ + OH-
0.20 M M pOH = -Log[OH-] = No ICE NH3 Weak Base NH3 + H2O ⇌ NH4+ + OH- I 0.20 M C x x x E x x x small Kb x2 = Kb = Kw = x = x 10-5 Ka x x = M pOH = -Log[ ] = 2.73 pH = 11.27

4 CaO Basic Anhydride CaO + H2O  Ca(OH)2
SO2 Acid Anhydride SO2 + H2O  H2SO3 Salts NaCl neutral salt NaCl  Na Cl- KCN basic salt CN H2O ⇌ HCN OH- hydrolysis NH4Cl acidic salt NH H2O ⇌ H3O NH3 hydrolysis

5 Fe(H2O)63+ ⇌ H+ + Fe(H2O)5(OH)2+ hydrolysis- copy off chart!
FeCl3 acidic salt Fe(H2O) ⇌ H+ + Fe(H2O)5(OH)2+ hydrolysis- copy off chart! Know the pH scale HCl HF NaCl NH NaOH Assuming 1M

6 Buffers Maintain the pH
Weak Acid Salt ( conjugate) HF KF HF ⇌ H F- High Low High Indicator Change colour with pH HInd ⇌ H Ind- Acid Low Basic

7 Indicators Change colour with pH
methyl red HInd ⇌ H Ind- red yellow page 7 @ trans pt [HInd] = [Ind-] colour is orange and Ka = [H+] pH = = 5.4 2 Ka = [H+] = = 4 x 10-6

8 Acid Rain SO2 NO2 pH  5 Normal Rain CO2 pH = 6 Amphriprotic H2C2O4 acid HC2O4- ampriprotic C2O42- base Is HC2O4- an acid or base? Ka (HC2O4-) = 6.4 x 10-5 Kb (HC2O4-) = 1.0 x = 1.7 x 5.9 x acid

9 Is NH4CH3COO an acid or base?
Ka (NH4+) = 5.6 x 10-10 Kb (CH3COO-) = 1.0 x = x 10-10 1.8 x neutral

10 100. 0 mL 0. 100 M H2SO4 is mixed with 220. 0 mL of 0. 100 M NaOH
100.0 mL M H2SO4 is mixed with mL of M NaOH. What is the pH of the resulting solution? H2SO NaOH L x mole L x mole 1 L L I mole mole C mole mole E 0 mole mole [NaOH] = mole = M 0.320 L pOH = 2.20 pH =

11 Complete the reaction and state if the reactants or products are favoured.
HCO HSO3- Base Acid HCO HSO3- ⇌ H2CO SO32- weaker weaker stronger stronger base acid acid base Reactants are favoured

12 Know the Equations E H2O ⇌ H+ + OH- Kw = [H+][OH-] = 1.0 x pH = -Log[H+] pOH = -Log[OH-] [H+] = 10-pH [OH-] = 10-pOH pH + pOH = pKw = @ 25 oC @ other temperatures pure water is always neutral & [H+] = [OH-] & pH = pOH  7


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