1. 6 Na (s) + Fe2O3 (s) ⟶ 3 Na2O3 (s) + 2 Fe (s).
23. The reaction between solid sodium and iron (III) oxide is one in a series of reactions that inflates an automobile airbag:
6 Na (s) + Fe2O3 (s) ⟶ 3 Na2O3 (s) + 2 Fe (s).
If g of Na and g of Fe2O3 are used in this reaction, determine the following:
Limiting reactant
Reactant in excess
Mass of solid iron produced

2. 6 Na (s) + Fe2O3 (s) ⟶ 3 Na2O3 (s) + 2 Fe (s).
100.0 g g ? g
6 mol Na
2 mol Fe
1 mol Fe2O3
= g Na
111.6 g Fe
= g Fe2O3
= g Na
X g Fe
= g Fe2O3
X = g Fe
X = g Fe
Na is in excess
Fe2O3 is limiting

3. 24. Challenge Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis.
Write a balanced chemical equation for reaction
Determine the limiting reactant
Determine the excess reactant
e) Determine the mass of glucose produced

4. 6 CO2 (g) + 6 H20 (l) → C6H12O6 (aq) + 6 O2 (g) 88.0 g 64.0 g ? g
6 mol CO2
1 mol C6H12O6
6 mol H20
= g CO2
180.0 g C6H12O6
= g H20
= g CO2
X g C6H12O6
= g H20
X = 107 g C6H12O6
X = g C6H12O6
H20 is in excess
CO2 is limiting

5. 28. Aluminum hydroxide (Al(OH)3) is often present in antacids to neutralize stomach acid (HCl). The reaction occurs as follows: Al(OH)3 (s) + 3 HCl (aq) ⟶ AlCl3 (aq) + 3 H2O (l) If 14.0 g of Al(OH)3 is present an antacid tablet determine the theoretical yield of AlCl3 produced when the tablet with HCl. 1 mol Al(OH)3 = 78.0 g Al(OH)3 = 14.0 g Al(OH)3 1 mol AlCl g AlCl3 X g AlCl3 X = 24.0 g AlCl3

6. Zinc reacts with iodine in a synthesis reaction:
29.
Zinc reacts with iodine in a synthesis reaction:
Zn + I2 ⟶ ZnI2
a) Determine the theoretical yield if mol of zinc is used.
1 mol Zn mol ZnI g ZnI2
1 mol ZnI mol ZnI2 = g ZnI2
b) Determine the percent yield if g of product is recovered.
g ZnI2 = %
610.3 g ZnI2

7. 30. Challenge When copper wire is placed into silver nitrate solution, silver crystals and copper(II) nitrate solution form.
Write a balanced chemical equation for the reaction
If 20.0-g sample of copper is used, determine the theoretical yield of silver.
If 60.0 g of silver is recovered from the reaction, determine the percent yield of the reaction.

8. Cu + 2 AgNO3 ⟶ Cu(NO3)2 + 2 Ag
20.0 g ? g
a) Determine the theoretical yield if 20.0 g of Cu is used.
1 mol Cu = g Cu = g Cu
2 mol Ag g Ag X g Ag = g Ag
b) Determine the percent yield 60.0 g of Ag is recovered.
60.0 g Ag = %
68.0g ZnI2