Download presentation
Presentation is loading. Please wait.
Published byÉmile Pothier Modified over 6 years ago
1
Will return graded Unit 2 tests on Friday for reflection.
11/30: Classify a triangle by its sides and angles. Do Now: Have Out: - Today’s Handouts Begin your Warm-Up Agenda: Warm-Up & Check Guided Notes Guided Practice Independent Practice Closing & HW (…maybe…) Homework Handout (5 problems + 2 EC Problems) Will return graded Unit 2 tests on Friday for reflection. 1st Period
2
Use the linear pair theorem to find the missing triangle angle measures:
Z Y X 30° 90° 30° 90° 60° 180° 60°
3
Triangle Sum Theorem
4
Classify a triangle by its sides and angles.
We will learn to: Classify a triangle by its sides and angles.
5
Graphic Organizer Use the examples and non-examples at your table to fill out your graphic organizer. Once you have finished, check with Mr. G BEFORE trying Examples 1 & 2
6
All 3 sides are congruent At least 2 congruent sides
No sides are congruent
7
All 3 angles are congruent
One right angle One obtuse angle All 3 angles are acute
8
How do we know it is obtuse?
Example 1: Classifying a Triangle by its Sides & Angles Right Triangle Isosceles Triangle Obtuse Triangle How do we know it is obtuse?
9
Example 2: Apply Properties of Isosceles & Equilateral Triangles
Check! 3x – 3 = 12 3(5) – 3 = 12 15 – 3 = 12 12 = 12
10
AB = BC 2x + 7 = 3x – 2 2x + 7 3x – 2 7 = x – 2 9 = x AB = 25 units
Example 2: Apply Properties of Isosceles & Equilateral Triangles AB = BC 2x + 7 = 3x – 2 2x + 7 3x – 2 7 = x – 2 9 = x 64° AB = 2x + 7 AB = 2(9) + 7 AB = AB = 25 units
11
Example 2: Apply Properties of Isosceles & Equilateral Triangles
∠BAC ≅ ∠BCA 52° 2x + 7 3x – 2 m∠BCA = 64° Triangle Sum Theorem 64° 64° m∠BAC + m∠BCA + m∠ABC = 180° ______ + ______ + ________ = 180° 64° 64° m∠BAC m∠ABC = 52°
12
Triangle Sum Theorem 6x + 18 = 180° 6x = 162 x = 27
Example 3: Apply Triangle Sum Theorem to Classify Triangles Triangle Sum Theorem (2x + 10)° m∠ABC + m∠ACB + m∠BAC = 180° (x + 20)° (3x - 12)° ______ + _______ + _______ = 180° (x + 20)° (3x – 12 )° (2x + 10)° 6x + 18 = 180° 6x = 162 x = 27
13
Example 3: Apply Triangle Sum Theorem to Classify Triangles
m∠ABC = (x + 20)° (2x + 10)° m∠ABC = 47° (x + 20)° (3x - 12)° m∠ACB = (3x – 12)° m∠ACB = 69° m∠BAC = (2x + 10)° m∠BAC = 64°
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.