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Building Java Programs Chapter 7
Arrays Copyright (c) Pearson All rights reserved.
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Can we solve this problem?
Consider the following program (input underlined): How many days' temperatures? 7 Day 1's high temp: 45 Day 2's high temp: 44 Day 3's high temp: 39 Day 4's high temp: 48 Day 5's high temp: 37 Day 6's high temp: 46 Day 7's high temp: 53 Average temp = 44.6 4 days were above average.
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Why the problem is hard We need each input value twice:
to compute the average (a cumulative sum) to count how many were above average We could read each value into a variable... but we: don't know how many days are needed until the program runs don't know how many variables to declare We need a way to declare many variables in one step.
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Arrays array: object that stores many values of the same type.
element: One value in an array. index: A 0-based integer to access an element from an array. index 1 2 3 4 5 6 7 8 9 value 12 49 -2 26 17 -6 84 72 element 0 element 4 element 9
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Array declaration type[] name = new type[length]; Example:
int[] numbers = new int[10]; index 1 2 3 4 5 6 7 8 9 value
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Array declaration, cont.
The length can be any integer expression. int x = 2 * 3 + 1; int[] data = new int[x % 5 + 2]; Each element initially gets a "zero-equivalent" value. Type Default value int double 0.0 boolean false String or other object null (means, "no object")
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Accessing elements name[index] // access
name[index] = value; // modify Example: numbers[0] = 27; numbers[3] = -6; System.out.println(numbers[0]); if (numbers[3] < 0) { System.out.println("Element 3 is negative."); } index 1 2 3 4 5 6 7 8 9 value 27 -6 index 1 2 3 4 5 6 7 8 9 value
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Arrays of other types double[] results = new double[5]; results[2] = 3.4; results[4] = -0.5; boolean[] tests = new boolean[6]; tests[3] = true; index 1 2 3 4 value 0.0 3.4 -0.5 index 1 2 3 4 5 value false true
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Out-of-bounds Legal indexes: between 0 and the array's length - 1.
Reading or writing any index outside this range will throw an ArrayIndexOutOfBoundsException. Example: int[] data = new int[10]; System.out.println(data[0]); // okay System.out.println(data[9]); // okay System.out.println(data[-1]); // exception System.out.println(data[10]); // exception index 1 2 3 4 5 6 7 8 9 value
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Accessing array elements
int[] numbers = new int[8]; numbers[1] = 3; numbers[4] = 99; numbers[6] = 2; int x = numbers[1]; numbers[x] = 42; numbers[numbers[6]] = 11; // use numbers[6] as index x 3 x index 1 2 3 4 5 6 7 value index 1 2 3 4 5 6 7 value 11 42 99 numbers
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Arrays and for loops It is common to use for loops to access array elements. for (int i = 0; i < 8; i++) { System.out.print(numbers[i] + " "); } System.out.println(); // output: Sometimes we assign each element a value in a loop. numbers[i] = 2 * i; index 1 2 3 4 5 6 7 value 8 10 12 14
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The length field An array's length field stores its number of elements. name.length for (int i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); } // output: It does not use parentheses like a String's .length(). What expressions refer to: The last element of any array? The middle element?
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Weather question Use an array to solve the weather problem:
How many days' temperatures? 7 Day 1's high temp: 45 Day 2's high temp: 44 Day 3's high temp: 39 Day 4's high temp: 48 Day 5's high temp: 37 Day 6's high temp: 46 Day 7's high temp: 53 Average temp = 44.6 4 days were above average.
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Weather answer // Reads temperatures from the user, computes average and # days above average. import java.util.*; public class Weather { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("How many days' temperatures? "); int days = console.nextInt(); int[] temps = new int[days]; // array to store days' temperatures int sum = 0; for (int i = 0; i < days; i++) { // read/store each day's temperature System.out.print("Day " + (i + 1) + "'s high temp: "); temps[i] = console.nextInt(); sum += temps[i]; } double average = (double) sum / days; int count = 0; // see if each day is above average for (int i = 0; i < days; i++) { if (temps[i] > average) { count++; // report results System.out.printf("Average temp = %.1f\n", average); System.out.println(count + " days above average");
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Quick array initialization
type[] name = {value, value, … value}; Example: int[] numbers = {12, 49, -2, 26, 5, 17, -6}; Useful when you know what the array's elements will be The compiler figures out the size by counting the values index 1 2 3 4 5 6 value 12 49 -2 26 17 -6
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"Array mystery" problem traversal: An examination of each element of an array. What element values are stored in the following array? int[] a = {1, 7, 5, 6, 4, 14, 11}; for (int i = 0; i < a.length - 1; i++) { if (a[i] > a[i + 1]) { a[i + 1] = a[i + 1] * 2; } index 1 2 3 4 5 6 value 7 10 12 8 14 22 index 1 2 3 4 5 6 value
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Limitations of arrays You cannot resize an existing array:
int[] a = new int[4]; a.length = 10; // error You cannot compare arrays with == or equals: int[] a1 = {42, -7, 1, 15}; int[] a2 = {42, -7, 1, 15}; if (a1 == a2) { ... } // false! if (a1.equals(a2)) { ... } // false! An array does not know how to print itself: System.out.println(a1); //
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Arrays as parameters
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Swapping values The red code should be replaced with:
public static void main(String[] args) { int a = 7; int b = 35; // swap a with b? a = b; b = a; System.out.println(a + " " + b); } What is wrong with this code? What is its output? The red code should be replaced with: int temp = a; b = temp;
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Array reversal question
Write code that reverses the elements of an array. For example, if the array initially stores: [11, 42, -5, 27, 0, 89] Then after your reversal code, it should store: [89, 0, 27, -5, 42, 11] The code should work for an array of any size. Hint: think about swapping various elements...
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Algorithm idea Swap pairs of elements from the edges; work inwards:
index 1 2 3 4 5 value 89 27 -5 42 11 index 1 2 3 4 5 value 89 -5 27 42 11 index 1 2 3 4 5 value 11 42 -5 27 89 index 1 2 3 4 5 value 89 42 -5 27 11
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Flawed algorithm What's wrong with this code?
int[] numbers = [11, 42, -5, 27, 0, 89]; // reverse the array for (int i = 0; i < numbers.length; i++) { int temp = numbers[i]; numbers[i] = numbers[numbers.length i]; numbers[numbers.length i] = temp; } The loop goes too far and un-reverses the array! Fixed version: for (int i = 0; i < numbers.length / 2; i++) {
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Array reverse question 2
Turn your array reversal code into a reverse method. Accept the array of integers to reverse as a parameter. int[] numbers = {11, 42, -5, 27, 0, 89}; reverse(numbers); How do we write methods that accept arrays as parameters? Will we need to return the new array contents after reversal? ...
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Array parameter (declare)
public static type methodName(type[] name) { Example: // Returns the average of the given array of numbers. public static double average(int[] numbers) { int sum = 0; for (int i = 0; i < numbers.length; i++) { sum += numbers[i]; } return (double) sum / numbers.length; You don't specify the array's length (but you can examine it).
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Array parameter (call)
methodName(arrayName); Example: public class MyProgram { public static void main(String[] args) { // figure out the average TA IQ int[] iq = {126, 84, 149, 167, 95}; double avg = average(iq); System.out.println("Average IQ = " + avg); } ... Notice that you don't write the [] when passing the array.
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Array return (declare)
public static type[] methodName(parameters) { Example: // Returns a new array with two copies of each value. // Example: [1, 4, 0, 7] -> [1, 1, 4, 4, 0, 0, 7, 7] public static int[] stutter(int[] numbers) { int[] result = new int[2 * numbers.length]; for (int i = 0; i < numbers.length; i++) { result[2 * i] = numbers[i]; result[2 * i + 1] = numbers[i]; } return result;
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Array return (call) Example: type[] name = methodName(parameters);
public class MyProgram { public static void main(String[] args) { int[] iq = {126, 84, 149, 167, 95}; int[] stuttered = stutter(iq); System.out.println(Arrays.toString(stuttered)); } ... Output: [126, 126, 84, 84, 149, 149, 167, 167, 95, 95]
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Arrays pass by reference
Arrays are passed as parameters by reference. Changes made in the method are also seen by the caller. public static void main(String[] args) { int[] iq = {126, 167, 95}; increase(iq); System.out.println(Arrays.toString(iq)); } public static void increase(int[] a) { for (int i = 0; i < a.length; i++) { a[i] = a[i] * 2; Output: [252, 334, 190] iq index 1 2 value 126 167 95 index 1 2 value 252 334 190 a
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Array reverse question 2
Turn your array reversal code into a reverse method. Accept the array of integers to reverse as a parameter. int[] numbers = {11, 42, -5, 27, 0, 89}; reverse(numbers); Solution: public static void reverse(int[] numbers) { for (int i = 0; i < numbers.length / 2; i++) { int temp = numbers[i]; numbers[i] = numbers[numbers.length i]; numbers[numbers.length i] = temp; }
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