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What if. . . You were asked to determine if psychology and sociology majors have significantly different class attendance (i.e., the number of days a person misses class) You would simply do a two-sample t-test two-tailed Easy!
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But, what if. . . You were asked to determine if psychology, sociology, and biology majors have significantly different class attendance You can’t do a two-sample t-test You have three samples No such thing as a three sample t-test!
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One-Way ANOVA ANOVA = Analysis of Variance
This is a technique used to analyze the results of an experiment when you have more than two groups
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Example You measure the number of days 7 psychology majors, 7 sociology majors, and 7 biology majors are absent from class You wonder if the average number of days each of these three groups was absent is significantly different from one another
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Hypothesis Alternative hypothesis (H1)
H1: The three population means are not all equal
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Hypothesis Alternative hypothesis (H1) socio = bio
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Hypothesis Alternative hypothesis (H1) socio = psych
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Hypothesis Alternative hypothesis (H1) psych = bio
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Hypothesis Alternative hypothesis (H1) psych = bio = soc
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Hypothesis Alternative hypothesis (H1)
Notice: It does not say where this difference is at!!
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Hypothesis Null hypothesis (H0) psych = socio = bio
In other words, all three means are equal to one another (i.e., no difference between the means)
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Results X = 3.00 X = 2.00 X = 1.00
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Logic Is the same as t-tests
1) calculate a variance ratio (called an F; like t-observed) 2) Find a critical value 3) See if the the F value falls in the critical area
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Between and Within Group Variability
Two types of variability Between / Treatment the differences between the mean scores of the three groups The more different these means are, the more variability!
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Between Variability Compute S2 on the means X = 3.00 X = 2.00 X = 1.00
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Between Variability S2 = 1 X = 3.00 X = 2.00 X = 1.00
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Between Variability + 5 X = 3.00 X = 2.00 X = 1.00
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Between Variability X = 8.00 X = 2.00 X = 1.00
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Between Variability Compute S2 on the means X = 8.00 X = 2.00 X = 1.00
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Between Variability S2 = 14.33 X = 8.00 X = 2.00 X = 1.00
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Between Group Variability
What causes this variability to increase? 1) Effect of the variable (college major) 2) Sampling error
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Between and Within Group Variability
Two types of variability Within / Error the variability of the scores within each group
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Within Variability Compute S2 within each group X = 3.00 X = 2.00
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Within Variability S2 =.67 S2 =1.67 S2 =.67 X = 3.00 X = 2.00 X = 1.00
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Within Group Variability
What causes this variability to increase? 1) Sampling error
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Between and Within Group Variability
Between-group variability Within-group variability
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Between and Within Group Variability
sampling error + effect of variable sampling error
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Between and Within Group Variability
sampling error + effect of variable sampling error Thus, if null hypothesis was true this would result in a value of 1.00
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Between and Within Group Variability
sampling error + effect of variable sampling error Thus, if null hypothesis was not true this value would be greater than 1.00
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Calculating this Variance Ratio
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Calculating this Variance Ratio
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Calculating this Variance Ratio
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Degrees of Freedom dfbetween dfwithin dftotal
dftotal = dfbetween + dfwithin
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Degrees of Freedom dfbetween = k - 1 (k = number of groups)
dfwithin = N - k (N = total number of observations) dftotal = N - 1 dftotal = dfbetween + dfwithin
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Degrees of Freedom dfbetween = k - 1 3 - 1 = 2
dfwithin = N - k = 18 dftotal = N = 20 20 =
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Sum of Squares SSBetween SSWithin SStotal
SStotal = SSBetween + SSWithin
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Sum of Squares SStotal
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Sum of Squares SSWithin
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Sum of Squares SSBetween
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Sum of Squares Ingredients: X X2 Tj2 N n
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To Calculate the SS
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X Xs = 21 Xp = 14 XB = 7
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X X = 42 Xs = 21 Xp = 14 XB = 7
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X2 X = 42 Xs = 21 Xp = 14 XB = 7 X2s = 67 X2P = 38 X2B = 11
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X2 X = 42 X2 = 116 Xs = 21 Xp = 14 XB = 7 X2s = 67 X2P = 38
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T2 = (X)2 for each group X = 42 X2 = 116 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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Tj2 X = 42 X2 = 116 Tj2 = 686 Xs = 21 Xp = 14 XB = 7 X2s = 67
T2P = 196 T2B = 49 T2s = 441
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N X = 42 X2 = 116 Tj2 = 686 N = 21 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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n X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 Xs = 21 Xp = 14 XB = 7
T2P = 196 T2B = 49 T2s = 441
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Ingredients X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7
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Calculate SS X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 SStotal
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Calculate SS 42 32 116 21 SStotal X = 42 X2 = 116 Tj2 = 686 N = 21
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Calculate SS X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 SSWithin
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Calculate SS 686 18 116 7 SSWithin X = 42 X2 = 116 Tj2 = 686 N = 21
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Calculate SS X = 42 X2 = 116 Tj2 = 686 N = 21 n = 7 SSBetween
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Calculate SS 14 686 42 7 21 SSBetween X = 42 X2 = 116 Tj2 = 686
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Sum of Squares SSBetween SSWithin SStotal
SStotal = SSBetween + SSWithin
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Sum of Squares SSBetween = 14 SSWithin = 18 SStotal = 32 32 =
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Calculating the F value
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Calculating the F value
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Calculating the F value
14 7 2
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Calculating the F value
7
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Calculating the F value
7 18 1 18
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Calculating the F value
7 7 1
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How to write it out
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Significance Is an F value of 7.0 significant at the .05 level?
To find out you need to know both df
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Degrees of Freedom Dfbetween = k - 1 (k = number of groups)
dfwithin = N - k (N = total number of observations)
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Degrees of Freedom Dfbetween = k - 1 3 - 1 = 2
dfwithin = N - k = 18 Use F table Dfbetween are in the numerator Dfwithin are in the denominator Write this in the table
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Critical F Value F(2,18) = 3.55 The nice thing about the F distribution is that everything is a one-tailed test
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Decision Thus, if F value > than F critical
Reject H0, and accept H1 If F value < or = to F critical Fail to reject H0
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Current Example F value = 7.00 F critical = 3.55
Thus, reject H0, and accept H1
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Alternative hypothesis (H1)
H1: The three population means are not all equal In other words, psychology, sociology, and biology majors do not have equal IQs Notice: It does not say where this difference is at!!
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How to write it out
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SPSS
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Conceptual Understanding
Complete the above table for an ANOVA having 3 levels of the independent variable and n = 20. Test for significant at .05.
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Conceptual Understanding
Fcrit = 3.18 Complete the above table for an ANOVA having 3 levels of the independent variable and n = 20. Test for significant at .05. Fcrit (2, 57) = 3.15
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Conceptual Understanding
Distinguish between: Between-group variability and within-group variability
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Conceptual Understanding
Distinguish between: Between-group variability and within-group variability Between concerns the differences between the mean scores in various groups Within concerns the variability of scores within each group
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Between and Within Group Variability
Between-group variability Within-group variability
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Between and Within Group Variability
sampling error + effect of variable sampling error
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Conceptual Understanding
Under what circumstance will the F ratio, over the long run, approach 1.00? Under what circumstances will the F ratio be greater than 1.00?
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Conceptual Understanding
Under what circumstance will the F ratio, over the long run, approach 1.00? Under what circumstances will the F ratio be greater than 1.00? F ratio will approach 1.00 when the null hypothesis is true F ratio will be greater than 1.00 when the null hypothesis is not true
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Conceptual Understanding
Without computing the SS within, what must its value be? Why?
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Conceptual Understanding
The SS within is 0. All the scores within a group are the same (i.e., there is NO variability within groups)
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Example Freshman, Sophomore, Junior, Senior Measure Happiness (1-100)
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ANOVA Traditional F test just tells you not all the means are equal
Does not tell you which means are different from other means
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Why not Do t-tests for all pairs Fresh vs. Sophomore Fresh vs. Junior
Fresh vs. Senior Sophomore vs. Junior Sophomore vs. Senior Junior vs. Senior
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Problem What if there were more than four groups?
Probability of a Type 1 error increases. Maximum value = comparisons (.05) 6 (.05) = .30
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Chapter 12 A Priori and Post Hoc Comparisons Multiple t-tests
Linear Contrasts Orthogonal Contrasts Trend Analysis Bonferroni t Fisher Least Significance Difference Studentized Range Statistic Dunnett’s Test
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Multiple t-tests Good if you have just a couple of planned comparisons
Do a normal t-test, but use the other groups to help estimate your error term Helps increase you df
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Remember
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Note
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Proof Candy Gender
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t = / .641 = 4.16
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t = / .641 = 4.16
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t = / .641 = 4.16
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t = / .641 = 4.16
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Also, when F has 1 df between
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Within Variability Within variability of all the groups represents “error” You can therefore get a better estimate of error by using all of the groups in your ANOVA when computing a t-value
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Note: This formula is for equal n
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Hyp 1: Juniors and Seniors will have different levels of happiness
Hyp 2: Seniors and Freshman will have different levels of happiness
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Hyp 1: Juniors and Seniors will have different levels of happiness
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Hyp 1: Juniors and Seniors will have different levels of happiness
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Hyp 1: Juniors and Seniors will have different levels of happiness
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Hyp 1: Juniors and Seniors will have different levels of happiness
t crit (20 df) = 2.086
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Hyp 1: Juniors and Seniors will have different levels of happiness
t crit (20 df) = 2.086 Juniors and seniors do have significantly different levels of happiness
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Hyp 2: Seniors and Freshman will have different levels of happiness
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Hyp 2: Seniors and Freshman will have different levels of happiness
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Hyp 2: Seniors and Freshman will have different levels of happiness
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Hyp 2: Seniors and Freshman will have different levels of happiness
t crit (20 df) = 2.086
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Hyp 2: Seniors and Freshman will have different levels of happiness
t crit (20 df) = 2.086 Freshman and seniors do not have significantly different levels of happiness
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Hyp 1: Juniors and Sophomores will have different levels of happiness
Hyp 2: Seniors and Sophomores will have different levels of happiness PRACTICE!
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