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The Law of Sines.

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Presentation on theme: "The Law of Sines."— Presentation transcript:

1 The Law of Sines

2 2.3 I can solve triangles using the Law of Sines

3 If none of the angles of a triangle is a right angle, the triangle is called oblique.
All angles are acute Two acute angles, one obtuse angle

4 To solve an oblique triangle means to find the lengths of its sides and the measurements of its angles.

5 FOUR CASES CASE 1: One side and two angles are known (SAA or ASA). CASE 2: Two sides and the angle opposite one of them are known (SSA). Ambiguous Case CASE 3: Two sides and the included angle are known (SAS). CASE 4: Three sides are known (SSS).

6 A S A ASA CASE 1: ASA or SAA Use Law of Sines S A A SAA

7 S A S CASE 2: SSA - Ambiguous Case Use Law of Sines

8 S A S CASE 3: SAS Use Law of Cosine

9 S S S CASE 4: SSS Use Law of Cosines

10 Theorem Law of Sines

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12 Case 1

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14 Case 1

15 The Ambiguous Case: Case 2: SSA
The known information may result in One triangle Two triangles No triangles

16 Case 2 Not possible, so there is only one triangle!

17

18 Case 2 Two triangles!!

19 Triangle 1:

20 Triangle 2:

21 No triangle with the given measurements!
Case 2 No triangle with the given measurements!

22 The Ambiguous Case: Case 2: SSA
The known information may result in One triangle Two triangles No triangles The key to determining the possible triangles, if any, lies primarily with the height, h and the fact h = b sin α a b h α

23 No Triangle If a < h = b sin α, then side a is not sufficiently long to form a triangle. a < h = b sin α b a h = b sinα α

24 One Right Triangle If a = h = b sin α, then side a is just long enough to form a triangle. a = h = b sin α b a h = b sinα α

25 Two Triangles If a < b and h = b sin α < a, then two distinct triangles can be formed a < b and h = b sin α < a a b a h = b sinα α

26 One Triangle If a ≥ b, then only one triangle can be formed. a ≥ b
Fortunately we do not have to rely on the illustration to draw a correct conclusion. The Law of Sines will help us. a b h = b sinα α


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