1. A 5 4 C 3 B
3 5
Sin A =

2. A 5 4 C 3 B
4 3
Tan B =

3. A 5 4 C 3 B
3 5
Cos B =

4. A 5 4 C 3 B
4 5
Cos A =

5. A 50 14 C 48 B
14 50 = 7 25
Cos A =

6. A 50 14 C 48 B
48 14 = 24 7
Tan A =

7. A 50 14 C 48 B
14 50 = 7 25
Sin B =

8. Soh
Cah
Toa
Sin (25) = 𝑥 10
10 sin(25) = x
x = 4.23m
10m x
25

9. Soh
Cah
Toa x
12cm
Tan (70) = 𝑥 12
12 tan(70) = x
x = 32.97cm
70

10. Soh Cah Toa x = 8 tan⁡(41) x = 9.20” x = 9.20” 41 Tan (41) = 8 𝑥8”
Tan (49) = 𝑥 8
8 tan(49) = x
x = 9.20” x
41
OR . . .

11. Soh Cah Toa x = 9.14 km 51 cos (51) = 5.75 𝑥 x cos(51) = 5.75

12. Soh
Cah
Toa
sin = 3 5
sin −1 ( 3 5 )=
36.9 =  5 3 

13. Soh
Cah
Toa
cos  =
cos −1 ( )=
48.6 =  8 
2 7

14. Find the measures of the acute angles in an 8-15-17 triangle
Since you have all 3 sides, you can use whichever ratio you want. I’m going to use sin to find , then subtract to find .
= 90 - 
= 90 – 32.2
= 61.9
sin = 8 17
sin −1 ( )=
28.1 =   8 15 17 