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CE 356 Elements of Hydraulic Engineering
Specific Energy (Alternate Depths) Hydraulic Jump (Sequent Depths)
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Energy in Open Channels
Specific Energy 11/17/2018
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Specific Energy, E E = energy (head) measured with respect to the channel bottom E = V2/2g + y = q2/(2gy2) + y Multiply through by y2 and arrange to find y3 – E y2 + q2/2g = 0 What kind of equation is this? How many roots? Significance of roots? 11/17/2018
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Specific Energy Diagram
Rectangular channel: B = 20 ft Q = 600 ft3/s. E = y Fr = 1 Fr = 2 Fr = V/(gy)0.5 11/17/2018
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Example: Sluice Gate q = 30 ft2/s y = 5.6 ft y = 1.8 ft 11/17/2018
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Note that there is head loss in an hydraulic jump
figure 1 Hydraulic jump Note that there is head loss in an hydraulic jump 11/17/2018
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Hydraulic jump on Rattan Creek, TX. July 2, 2002
strong jump: Fr > 9.0, rough wavy surface downstream steady jump: 4.5<Fr < 9.0, stable and well-balanced 11/17/2018
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classification Classification 11/17/2018
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picture 11/17/2018
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figure 2 11/17/2018
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Now let’s consider an hydraulic jump
jump cv Now let’s consider an hydraulic jump We know that or 11/17/2018
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rearranging and dividing by g:
momentum balance Our momentum balance can be written as rearranging and dividing by g: Using A=By for a rectangular channel Let’s go back to our hydraulic jump… 11/17/2018
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solvable set If we have an open channel where we know Q, B, and y1, we can solve for y2 11/17/2018
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Recalling the definition of the flow rate per unit width
rectangular Starting from Recalling the definition of the flow rate per unit width we can obtain Solving for y2 y1 solution is similar (see text) 11/17/2018
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Now, what are the limitations of this equation?
limits Now, what are the limitations of this equation? shear forces are neglected shear causes smaller head loss than turbulence in the jump requires jump occurs over a short distance rectangular channel effect of gravity downslope is neglected again requires jump to occur over a short distance neglect non-hydrostatic pressure uniform density fluid 11/17/2018
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…and what is the fundamental principle for this equation?
conservation of momentum 11/17/2018
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E–M graphs 11/17/2018
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The more general head loss formula is
Valid for any cross section 11/17/2018
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