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Published byΝικομήδης Βλαστός Modified over 6 years ago
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X-rays absorption Long Wave IR Visible UV X-rays Gamma rays
Long Wave IR Visible UV X-rays Gamma rays wavelength (nm) absorption X-rays
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I/Io = e -µ* x = 1/ e µ* x = 1/ e µ x
Absorption Io I X-rays x I/Io = e -µ* x = 1/ e µ* x = 1/ e µ x µ* = linear attenuation coefficient µ = mass attenuation coefficient = density of absorber
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Absorption µ - values for elements listed in various texts & International Tables for Crystallography Note that µ changes with X-ray wavelength Higher atomic no. ––> larger µ, in general
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Absorption What element used for X-ray tube windows? What element used for protection from X-rays?
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µcompd or mixture = (wt. fraction)element x µelement
Absorption Io I X-rays x I/Io = e -µ* x = 1/ e µ* x = 1/ e µ x For compounds & mixtures, calculate µ from µcompd or mixture = (wt. fraction)element x µelement
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I/Io = e -µ* x = 1/ e µ* x = 1/ e µ x
Absorption Io I X-rays x I/Io = e -µ* x = 1/ e µ* x = 1/ e µ x Example for NaCl (CuK: (wt. fraction)Na = 23/58.5 = 0.393, (wt. fraction)Cl = 0.607 µNa = µCl = 106 µNaCl = (wt. fraction)Na x µNa + (wt. fraction)Cl x µCl µNaCl = x x .607 = 76.2
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Absorption Mass attenuation coefficient for an element changes with
X-ray wavelength (energy) like this: mass attenuation coefficient <–– energy wavelength ––> Kedge Good news/bad news
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Absorption Bad news Absorbed energy re-emitted as fluorescent X-rays
Suppose: mass attenuation coefficient <–– energy wavelength ––> Kedge absorption for element in specimen X-ray wavelength used for diffraction Then: Absorption high Lots of fluorescence
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Absorption Bad news X-ray fluorescence radiation emitted at all angles
X-rays detector specimen X-ray fluorescence radiation emitted at all angles 2 2 I instead of this: 2 I get this:
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Absorption Good news - -filters
-filter materials have atomic nos. 1 or 2 less than anode 50-60% beam attenuation
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Absorption Good news - -filters
placing after specimen/before detector filters most of specimen fluorescence X-rays detector filter specimen
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