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Entropy = S Entropy is disorder or randomness
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2nd Law of Thermodynamics
Suniverse > 0 for spontaneous processes spontaneous = no external intervention Ssystem Ssurroundings positional disorder energetic disorder
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Energetic Disorder P.E. K.E. random ordered a) endothermic reaction
b) random ordered reactants a) endothermic reaction b) exothermic reaction P.E. Hsystem 0 < products Hsurroundings 0 > Ssurroundings > 0
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Ssurr depends on T Ssurr = - Hsystem (J/K) T heat surroundings
high T small effect low T relatively larger effect
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Positional Disorder With 1 mole of gas, Not probable (1/2) (1/2) (1/2)
= 1/64 With 1 mole of gas, Not probable
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Positional Disorder Boltzman ordered states low probability low S
RIP S = k ln W W = degrees of freedom Boltzman ordered states low probability low S disordered states high probability high S Ssystem Positional disorder Increases with number of possible positions (energy states) Ssolids < Sliquids << Sgases
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Entropy (J/K) [heat entering system at given T] convert q to S
Pext = 1.5 atm E = 0 w = -182 J q = +182 J T = 298 K E = 0 System 2 Pext = 0 atm w = 0 q = 0
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Pext = Pint + dP System 3 reversible process - infinitely slow wr=
P1 = 6.0 atm P2 = 1.5 atm V1 = 0.4 L V2 = 1.6 L T1 = 298 K = T2 Pext = Pint + dP reversible process - infinitely slow V2 wr= - Pext dV =- nRT dV V = - nRT ln (V2/V1) V1
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Ssystem Ssurr = - Hsystem Ssystem = qr = 1120 J T T 298 K System 1
Pext = 1.5 atm w = -182 J q = +182 J S = System 2 Pext = 0 atm w = 0 q = 0 S = System 3 Pext = Pint + dP wr = qr = S = -nRT ln (V2/V1) = J J 3.77 J/K 3.77 J/K 3.77 J/K Ssurr = - Hsystem T Ssystem = qr T = 1120 J 298 K
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3rd Law of Thermodynamics
Entropy of a perfect crystalline substance at 0 K = 0
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Entropy curve S Temperature (K) gas liquid solid vaporization qr T
fusion Temperature (K)
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Entropy At 0K, S = 0 Entropy is absolute S 0
for elements in standard states S is a State Function Sorxn = nSoproducts - nSoreactants S is extensive
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Increases in Entropy 1. Melting (fusion) Sliquid > Ssolid
2. Vaporization Sgas >> Sliquid 3. Increasing ngas in a reaction Heating ST2 > ST1 if T2 > T1. Dissolution Ssolution > (Ssolvent + Ssolute) ? 6. Molecular complexity number of bonds 7. Atomic complexity e-, protons and neutrons
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