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Chain Rule AP Calculus
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π¦= ( 2π₯ 2 +3π₯β1) 8 Differentiate
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π¦= ( 2π₯ 2 +3π₯β1) 8 π¦ β² =8 ( 2π₯ 2 +3π₯β1) 7 (4x+3)
Differentiate
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π¦= cos 3π₯ Find the derivative
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π¦= cos 3π₯ yβ = -sin 3x β3 yβ = -3 sin 3x
Find the derivative
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π¦= 1 ( 2π₯ 5 β7) 3 y = ( 2π₯ 5 β7) β3 dy/dx = β3 ( 2π₯ 5 β7) β4 β 10π₯ 4 = β30 π₯ 4 ( 2π₯ 5 β7) β4
Find dy/dx
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π π₯ = 2π₯+1 π₯ Find the derivative
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π π₯ = 2π₯+1 π₯ = 2 + 1 π₯ = 2 + π₯ β1 fβ(x) = β π₯ β2
Find the derivative
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π π₯ =sinβ‘( π₯ 2 +1) Differentiate
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π π₯ =sinβ‘( π₯ 2 +1) gβ(x) = cos( π₯ 2 +1)β2π₯ = 2x cos( π₯ 2 +1)
Differentiate
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π¦= π ππ 4 π₯ Find yβ
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π¦= π ππ 4 π₯ y = ( sin π₯) 4 yβ = 4 ( sin π₯) 3 β cos π₯
Find yβ
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π π₯ = πππ 2 3π₯ Find the derivative
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π π₯ = πππ 2 3π₯ fβ(x) = 2(cos 3x) β(β sin 3π₯)β3 fβ(x) = -6sin 3x cos 3x
Find the derivative
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