Presentation is loading. Please wait.

Presentation is loading. Please wait.

Reaction Mechanisms -- the processes by which reactions occur --

Similar presentations


Presentation on theme: "Reaction Mechanisms -- the processes by which reactions occur --"— Presentation transcript:

1 Reaction Mechanisms -- the processes by which reactions occur -- i.e., what happens in getting from R to P -- sometimes, mechanisms are dependent on temp.

2 (or elementary reactions):
elementary steps (or elementary reactions): R turn to P in a single step A reaction’s molecularity is defined by the number of particles that participate as reactants in an elementary step. unimolecular bimolecular termolecular CH3CN CH3NC NO + O NO2 + O2 very rare

3 For multistep mechanisms, sequences of elementary steps
are needed to go from R to P. e.g., For the reaction NO2 + CO NO + CO2 Elem. Step 1: Elem. Step 2: these must add to give the overall reaction NO2 + NO NO + NO3 NO3 + CO NO2 + CO2 NO2 + CO NO + CO2 Above, NO3 is an intermediate. All multistep mechanisms have them.

4 rate = k [A] rate = k [A]2 rate = k [A] [B] rate = k [A]3
The rate law and relative speed of each elementary step (no matter how many there are) determine the overall rate law for the reaction; that is, the mechanism gives us the overall rate law. Rate laws for the elementary steps are found as follows... A + B + C P ter- A + A + B P A + A + A P A + B P bi- A + A P A P uni- Rate Law for that Elementary Step Molecularity rate = k [A] rate = k [A]2 rate = k [A] [B] rate = k [A]3 rate = k [A]2 [B] rate = k [A] [B] [C] These rate laws are for elementary steps, not necessarily for the R P reaction.

5 Most reactions have multiple elementary steps.
The slowest of these is the... rate-determining step. In producing vegetables from a garden, the rate-determining step is the growing of the food itself. The correct rate law for a reaction must: 1) be based on… the r-d step 2) have only… REACTANTS in it (NOT intermediates).

6 CHCl3(g) + Cl2(g) CCl4(g) + HCl(g) has the following elementary steps:
E. S. 1: Cl Cl (fast, eq) E. S. 2: CHCl3 + Cl  CCl3 + HCl (slow) E. S. 3: CCl3 + Cl  CCl4 (fast) State the rate law and the units on the rate constant. (not a REACTANT) rate = k2 [CHCl3][Cl] For fast eq. steps, you can write a rate law in either dir. e.g., eq rate = k1f[Cl2] = k1r[Cl]2  [Cl] = (k1f/k1r [Cl2])1/2 sub. this in for [Cl] above So rate = k [CHCl3][Cl2]1/2 units on k = M–1/2 s–1


Download ppt "Reaction Mechanisms -- the processes by which reactions occur --"

Similar presentations


Ads by Google