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Warm β up #7 1. Solve by Factoring 3 π₯ 2 βπ₯=2 2. Solve by Factoring 2 π₯ 2 =72 3. Solve π₯ 2 =β5π₯ 4. Solve by Square Root (π₯+3) 2 =β20
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Warm β up #7 Solutions β6 1. Solve by Factoring 3 π₯ 2 βπ₯=2 3 π₯ 2 βπ₯β2=0 3 π₯ 2 β3π₯+2π₯β2=0 3x(x β 1) + 2(x β 1) = 0 (3x + 2)(x β 1) = 0 3x + 2 = 0 x β 1 = 0 x = 1, β 2 3 β3 2 β1
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Warm β up #7 Solutions 2. Solve by factoring 2 π₯ 2 =72 2 π₯ 2 β72=0 2( π₯ 2 β36)=0 = ( ) 2 β 2 = 2(x β 6)(x + 6) x β 6 = 0 x + 6 = 0 x = Β±6 x 6
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Warm β up #7 Solutions 3. Solve π₯ 2 =β5π₯ π₯ 2 +5π₯=0 x(x + 5) = 0 x = 0, β5 4. Solve by Square Root (π₯+3) 2 =β20 x + 3 = Β±2π 5 x=β3Β±2π 5
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Homework Log Thurs 11/12 Lesson 4 β 6 Learning Objective:
To solve quadratic equations by factoring Hw: Lesson 4 β 6 WS
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11/12/15 Lesson 4 β 6 Completing the Square
Algebra II
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Learning Objective To solve quadratic equations by completing the square
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Complete the Square 1. π₯ 2 +2π₯+_____ = (π₯+1) 2 1 2. π₯ 2 +4π₯+_____
2. π₯ 2 +4π₯+_____ = (π₯+2) 2 4
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Complete the Square 3. π₯ 2 +6π₯+_____ = (π₯+3) 2 9 4. π₯ 2 +8π₯+____
4. π₯ 2 +8π₯+____ = (π₯+4) 2 16
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Complete the Square 5. π₯ 2 +10π₯+_____ = (π₯+5) 2 25 7. π₯ 2 β20π₯+_____
7. π₯ 2 β20π₯+_____ = (π₯β10) 2 100 6. π₯ 2 β2π₯+____ = (π₯β1) 2 1 8. π₯ 2 β14π₯+____ = (π₯β7) 2 49
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Complete the Square To Complete the Square π₯ 2 +ππ₯+_____
π₯ 2 MUST have a coefficient of 1 π goes in the blank π 2 goes into the perfect square (π₯+ π 2 ) 2 π₯ 2 β12x+c
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Solve by Square Root 9. (2π₯+3) 2 = 4 2x + 3 = Β±2 2x = β 3 Β± 2 x = β3 Β± 2 2 x = β x = β3 β 2 2 donβt forget! β1 2 , β5 2
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Solve by Completing the Square
10. π₯ 2 β14π₯+49 = 4 β 49 β 49 π₯ 2 β14π₯ = β 45 + β = (β7) 2 =49 (π₯β7) 2 =4 x β 7 = Β±2 x = 7Β±2 x = = 9 x = 7 β 2 = 5 49 49 5, 9
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Solve by Completing the Square
11. π₯ 2 +6π₯ = β8 π₯ 2 +6π₯ = β 8 + = (3) 2 =9 (π₯+3) 2 =1 x +3 = Β±1 x = β3Β±1 x = β = β2 x = β3 β 1 = β4 9 9 β2, β4
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Solve by Completing the Square
12. π₯ 2 β8π₯+28 = 4 β 28 β 28 π₯ 2 β8π₯+ = β 24 + β8 2 2 = (β4) 2 =16 (π₯β4) 2 =β8 x β 4 = Β±2π 2 16 16 4Β±2π 2
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Solve by Completing the Square
13. π₯ 2 +6π₯+13 = 0 β 13 β 13 π₯ 2 +6π₯+ = β = (3) 2 =9 (π₯+3) 2 =β4 x + 3 = Β±2π 9 9 β3Β±2π
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Solve by Completing the Square
14. 8π₯ 2 β16π₯+104 = 8 β 104 β 104 8π₯ 2 β16π₯ = β π₯ 2 β2π₯+ = β12 + β2 2 2 = (β1) 2 =1 (π₯β1) 2 =β11 π₯β1 = Β±π 11 1Β±π 11 1 1
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Solve by Completing the Square
Divide every term by leading coeff. 15. 2π₯ 2 β2π₯+1 = π₯ 2 βπ₯+ 1 2 = 0 β 1 2 β 1 2 π₯ 2 βπ₯+ = β β1 2 2 = 1 4 (π₯β 1 2 ) 2 =β 1 4 π₯β = Β± π 2 1 2 Β± π 2 or { 1Β±π 2 } 1 4 1 4
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Solve by Completing the Square
16. π₯ 2 +3π₯+12 = 0 β 12 β 12 π₯ 2 +3π₯+ = β = 9 4 π₯ =β 39 4 π₯+ 3 2 = Β±π β 3 2 Β± π or β3Β±π 9 4 9 4
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Ticket Out the Door 2π₯ 2 β20π₯=β44 Solve by Completing the Square
Solve by Quadratic Formula Do you get the same answer?
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Assignment: Lesson 4 β 6 WS
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