1. Dr. Namphol Sinkaset Chem 200: General Chemistry I
Ch. 10: Liquids and Solids
Dr. Namphol Sinkaset
Chem 200: General Chemistry I

2. I. Chapter Outline Introduction Intermolecular Forces
Phase Transitions
Phase Diagrams

3. I. Condensed States
Liquids and solids are the condensed states because of the close proximity of atoms/molecules to one another.
This proximity leads to much more frequent interactions than in gases.
Interactions depend on chemical identity of the substance and determine many physical properties.

4. II. States of Matter
The state of a sample if matter is the result of a battle between attractive forces between particles and kinetic energy.

5. II. Electrostatic Forces
Every molecule in a sample of matter experiences two types of electrostatic forces.
Intramolecular forces: the forces that exist within the molecule (bonding). These forces determine chemical reactivity.
Intermolecular forces: the forces that exist between molecules. These forces determine physical properties.

6. II. Intermolecular Forces
Intermolecular forces are attractive forces that originate from interactions between charges, partial charges, and temporary charges on molecules.

7. II. Types of IM Forces
There are different kinds of IM forces, each with a different level of strength.
Dispersion forces
Dipole-dipole attractions
*Hydrogen “bonding”

8. II. Dispersion Forces
Dispersion forces (London forces) are present in all molecules and atoms and results from changes in e- locations.

9. II. Instantaneous Dipoles
Charge separation in one creates charge separation in the neighbors.

10. II. Dispersion Force Strength
The ease with which e-’s can move in response to an external charge is known as polarizability.
Large atoms with large electron clouds tend to have stronger dispersion forces.
Larger molecules tend to have stronger dispersion forces.

11. II. Noble Gas Boiling Points

12. II. Dispersion Forces and Shape
Molecular size is not the only factor…

13. II. Dispersion Forces in a Family

14. II. Dispersion Forces in Action

15. II. Dipole-Dipole Attractions
Occur in polar molecules which have permanent dipoles, so attraction is always present.

16. II. Hydrogen “Bonding”
This IM force is a misnomer since it’s not an actual bond.
Occurs between molecules in which H is bonded to a highly electronegative element (N, O, F), leading to high partial positive and partial negative charges.
It’s a “super” dipole-dipole attraction.

17. II. H “Bonding” Water

18. II. Boiling Point Trend

19. II. Effect of H “Bonding”

20. II. Sample Problem
Which substance has the highest boiling point and why?
CH3OH CO N2

21. III. Vaporization and IM Forces
From experience, we know that water evaporates in an open container.
What factors influence rate of vaporization?

22. III. Vaporization Variables
Temperature
Surface area
IM forces

23. III. Energetics of Vaporization
As molecules evaporate, what happens to the temperature of the samples left in the beaker?
Vaporization is an endothermic process – it’s the reason why we sweat when we get too hot.
Condensation is an exothermic process.

24. III. Dynamic Equilibrium
In an open flask, a liquid will eventually evaporate away.
What about a closed flask?

25. III. Vapor Pressure

26. III. Vapor Pressure and Temp.
Vapor pressure depends on temperature and IM forces.
Why?

27. III. Boiling Point
When T is increased, the vapor pressure increases due to the higher # of molecules that can break away and enter gas phase.
What if all molecules have necessary thermal energy?
At this point, vapor pressure = external pressure, and boiling point is reached.
The temperature at which vapor pressure equals 1 atm is the normal boiling point.

28. III. Boiling Point vs. Altitude

29. III. Pvap – T Relationship
The Clausius-Clapeyron equation describes the relationship between vapor pressure and temperature.

30. III. Linear Form This equation is in linear form, y = mx + b.
The heat of vaporization can be found using graphical analysis.
Use R = J/mole·K.

31. III. Graphical Analysis

32. III. Clausius-Clapeyron Equation, 2-point Form
If you have two sets of pressure, temperature data for a liquid, the more convenient 2-point form of the Clausius-Clapeyron equation can be used.

33. III. Sample Problem
Propane has a normal boiling point of °C and a heat of vaporization of kJ/mole. What is the vapor pressure of propane at 25.0 °C?

34. III. Other Phase Changes
Sublimation is the direct conversion of particles from the solid phase to the gas phase.
Average KE is low, but always some that have enough KE to break away.
Fusion is the conversion of solid to liquid.
Also have deposition and freezing.

35. III. Energetics of Fusion
Different compounds have different heats of fusion.
Notice they are much lower than heats of vaporization – why?

36. III. Energies of Phase Changes
The enthalpies involved in a phase change depends on the amount of substance and the substance itself.
We look at a heating curve for H2O at 1.00 atm pressure.
Note that there are sloping regions and flat regions in the curve. (Why?)

37. III. Heating Curve for H2O

38. III. Heating Curve, Sloped Regions
In these regions, heat is being used to increasing KE – hence changes in T.
The heat required depends on the specific heat capacity of the phase.

39. III. Heating Curve, Flat Regions
Here, the temperature stays the same, so the average KE stays the same.
Thus, the PE must be increasing.
The heat gained is a factor of the ΔH of the phase change.

40. IV. Phase Diagrams
Measurements of phase transitions over a variety of different temperatures and pressures are used to construct phase diagrams.
Phase diagrams allow predictions of the phase in which a substance will exist under specific conditions.

41. IV. Generic Phase Diagram

42. IV. Phase Diagram for H2O

43. IV. The Critical Point
In a sealed container, as T of liquid is heated, more and more vapor is formed, and P increases.
At the critical temperature, a supercritical fluid forms; liquid can’t exist above this temperature.