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Solving Quadratic Equations
ALGEBRA 1 LESSON 9-4 Remember = 6 2. – = –9 3. ± = ± = 1.2 = ± = ±1.1 = 8. ± = ± 9. ± = ± 1 4 1 2 1 9 1 3 49 100 7 10 9-4
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Solving Quadratic Equations
ALGEBRA 1 LESSON 9-4 Solve each equation by graphing the related function. a. 2x2 = 0 b. 2x2 + 2 = 0 c. 2x2 – 2 = 0 Graph y = 2x2 Graph y = 2x2 + 2 Graph y = 2x2 – 2 There is one solution, x = 0. There is no solution. There are two solutions, x = ±1. 9-4
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Solving Quadratic Equations
ALGEBRA 1 LESSON 9-4 Solve 3x2 – 75 = 0. 3x2 – = Add 75 to each side. 3x2 = 75 x2 = 25 Divide each side by 3. x = ± Find the square roots. x = ± 5 Simplify. 9-4
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Solving Quadratic Equations
ALGEBRA 1 LESSON 9-4 A museum is planning an exhibit that will contain a large globe. The surface area of the globe will be 315 ft2. Find the radius of the sphere producing this surface area. Use the equation S = 4 r2, where S is the surface area and r is the radius. S = 4 r 2 315 = 4 r 2 Substitute 315 for S. Put in calculator ready form. 315 (4) = r 2 = r 2 315 (4) Find the principle square root. r Use a calculator. The radius of the sphere is about 5 ft. 9-4
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Solving Quadratic Equations
ALGEBRA 1 LESSON 9-4 1. Solve each equation by finding square roots. If the equation has no solution, write no solution. a. 2x2 – 8 = 0 b. x2 + 2 = –2 2. Solve each equation by finding square roots. a. m2 – 25 = 0 b. 49q2 = 9 3. Find the speed of a 4-kg bowling ball with a kinetic energy of 160 joules. Use the equation E = ms2, where m is the object’s mass in kg, E is its kinetic energy, and s is the speed in meters per second. ±2 no solution ±5 3 7 1 2 about 8.94 m/s 9-4
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