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Chapter 5 Notes: Energetics Thermochemistry
Chapter 5.1: The enthalpy changes from chemical reactions can be calculated from their effect on the temperature of their surroundings.
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Important terms for this section
Energy Work System Surroundings Open and closed systems Enthalpy Endothermic Standard enthalpy changes Absolute zero Kelvin scale Heat capacity
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Energy and heat transfer energy
Energy: measured in Joules = kg*m2/s2 = N*m Ability to do work Ability to move an object against an opposing force Some forms Heat, Light, Sound, Electricity, Chemical energy Focus is heat in this unit = E transfer with Temp diff. Inc. heat = inc. ave. K.E. of molecules in a disordered fashion
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System and surroundings
System: area of interest Surroundings: everything else Open system Can exchange energy AND matter with surroundings Closed system Can exchange energy ONLY with surroundings Total Energy cannot change during process only exchange
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Enthalpy Enthalpy “heat inside”: heat content of a system
Changes in enthalpy is noted: ΔH If heat is added to a system, enthalpy increases (is positive) If heat is released from system, enthalpy decreases (negative)
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Exothermic & endothermic
Exo = release (external) exothermic releases heat Might feel hot when reacting Giving out heat means a negative enthalpy change Ereactants > Eproducts Endo = take in endothermic needs heat Might feel cold when reacting Heat added to the system means a positive enthalpy change Ereactants < Eproducts
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Standard enthalpy changes
Symbol for standard enthalpy change: ΔHѳ Conditions Pressure of 100 kPa Concentration = 1 mol dm-3 for all solutions All substances in their standard states Temp is not part of definition, but is typically 298K
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Thermochemical equations
Combustion of methane: Releases 890 kj mol-1 of heat energy Photosynthesis: Absorbs kj mol-1 of energy
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Kelvin and kinetic energy
Average kinetic energy of molecules related to Kelvin Absolute zero Absolute temp directly proportional to average KE particles If same amt of heat is added to 2 different objects, will temp change be the same? Heat changes depend on Mass of object Heat added Nature of substance
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Heat changes continued
Specific heat capacity Amount of heat needed to increase the temp of unit mass by 1K Depends on Number of particles present in the sample And therefore the mass of individual particles Heat capacity Amount of heat needed to increase temp of an object 1K
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Heat capacities So, to recap:
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Enthalpy and direction of change
Energy moves from higher to lower stored energy And might look different than you assume
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Measuring/calculating Enthalpy changes
Measuring enthalpy changes of Combustion, ΔHcѳ The enthalpy change for the complete combustion of 1 mole of a substance in its standard state in excess oxygen under STP. Calorimetry
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Measuring/calculating Enthalpy changes
Calculating ΔH from Temperature changes For Exothermic RXN Temp of H2O increases ΔH is negative For Endothermic RXN Temp of H2O decreases ΔH is postitive
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Measuring/calculating Enthalpy changes
ΔHsol of RXN in solution The enthalpy change when 1 mole of solute is dissolved in excess solvent to form a solution of ‘infinite dilution’ under std. conditions The results are not always what you expect Loss of heat to environment/ materials/etc. vs water
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Definitions ΔHѳ standard enthalpy change
Change in enthalpy under std. conditions 100kPa, 298K ΔHѳr standard enthalpy change of reaction Enthalpy change when molar amounts of reactants, as shown in a stoichiometric equation react together under std. conditions to give products ΔHѳc standard enthalpy change of combustion Enthalpy change when 1 mole of a substance is completely burnt in oxygen under std. conditions
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definitions ΔHn enthalpy change of neutralization
Enthalpy change when 1 mole of water molecules are formed when an acid (H+) reacts with an alkali (OH-) under std. conditions ΔHsol of RXN in solution The enthalpy change when 1 mole of solute is dissolved in excess solvent to form a solution of ‘infinite dilution’ under std. conditions c specific heat capacity The energy required to raise the temperature of 1kg (or 1g) of a substance by 1K (1ºC) q heat energy How much heat energy must be supplied to raise the temp of mass m by ΔTºC q=mc ΔT
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Problem 1 Using the data, determine the ΔHѳc of ethanol (C2H5OH) given that the cH2O = 4.18 J g-1 ºC-1 (remember c is specific heat capacity) Mass of water = g Initial temp of water = 19.5 ºC Maximum temp of water = 45.7 ºC Initial mass of spirit burner = g Final mass of spirit burner = g REMEMBER: ΔHѳc is the enthalpy change when 1 mole of a substance is completely burnt in oxygen under std. conditions
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Problem 1 solution So if ΔHѳc is the enthalpy change when 1 mole of a substance is completely burnt in oxygen under std. conditions We need to find: The heat energy change (how many Joules are being produced) How many moles are being burned of ethanol
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Problem 1 solution Plug in the values:
Amount of energy supplied to the water: Use q =mcΔT c: given as 4.18 J g-1 ºC-1 ΔT: = 26.2 ºC m: g water Plug in the values: q = x 4.18 x 26.2 = J And is the heat energy supplied by the burning of ethanol
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Problem 1 solution How many moles of ethanol are burned
Initial mass of spirit burner = g Final mass of spirit burner = g So, Mass burned = – = 1.05 g Convert to moles ethanol (46.08 g mol-1) 1.05 g (1 mol/46.08 g) = mol ethanol Therefore, when mol ethanol are burned, it produces J heat Convert to 1 mol: J/ mol = J mol-1 Thus, ΔH = -721 kJ mol-1
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Problem 1 solution Now, let’s compare the calculated value with the literature value ΔH = -721 kJ mol-1 ΔHѳc = kJ mol-1 Why are they so different? Heat loss to surroundings Some heat goes to heating copper can and air Incomplete combustion of ethanol Evaporation of ethanol and water Improvements: Taken into account the c of the can in calculations Insulating the can Use other kind of calorimeter
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Problem 2 Consider the experiment:100.0 cm3 of water are measured out and poured into a polystyrene cup and the temp of the water measured. Then 5.20 g ammonium chloride are measured out. The ammonium chloride was added to the water and the solution stirred vigorously until all the solute dissolved. The minimum temp was recorded. Results: Initial temp of water = 18.3 ºC Minimum temp = 15.1 ºC Find the enthalpy change of solution for ammonium chloride, ΔHsol Remember: The enthalpy change when 1 mole of solute is dissolved in excess solvent to form a solution of ‘infinite dilution’ under std. conditions
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The specific heat capacity of the solution is the same as water
Problem 2 hints What do you need to do? Find the enthalpy change of solution for ammonium chloride, ΔHsol The enthalpy change when 1 mole of solute is dissolved in excess solvent to form a solution of ‘infinite dilution’ under std. conditions Actual data you have: 100.0 cm3 water (so actually g water) Initial temp of water = 18.3 ºC Minimum temp = 15.1 ºC 5.20 g ammonium chloride You will make the following assumption: The specific heat capacity of the solution is the same as water
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Problem 3 The following experiment may be used to determine the enthalpy of reactions for: Zn(s) + CuSO4(aq) ZnSO4(aq) + Cu(s) 50.0 cm3 of mol dm-3 copper(II) sulfate solution are placed in a polystyrene cup. The temperature was recorded every 30s for 2 min. At 2 min every 30s for 2 min. At 2 min 30s, 1.20 g of powdered zinc are added. The mixture was stirred vigorously and the temp recorded every 30s for several minutes. The results obtained were then plotted to give the graph shown Use these data to determine the enthalpy change for this reaction.
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Problem 3 hints Determine the enthalpy change for this reaction.
Remember: ΔHѳr standard enthalpy change of reaction Enthalpy change when molar amounts of reactants, as shown in a stoichiometric equation react together under std. conditions to give products Data you actually have: Zn(s) + CuSO4(aq) ZnSO4(aq) + Cu(s) 50.0 cm3 of mol dm-3 CuSO4(aq) The graph to the right By extrapolating back to the area above the start of the reaction, Temp change, ΔT = 10.3 ºC 1.20 g Zn(s) Assumption: density of CuSO4 solution = water therefore the m and c are the same as water 50.0 g and 4.18
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