1. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T =

2. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s

3. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no

4. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2

5. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ?

6. Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ? T = 7 sec.

7. Solution #1 D = V 1 t + at 2 2

8. Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2

9. Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2 D = 150 m

10. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = V 2 = A = D = T =

11. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ?

12. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s

13. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2

14. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m

15. Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m T = no

16. Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad

17. Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s)( 484 m)

18. Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2

19. Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2 V 1 = 88 m/s

20. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = V 2 = A= D= T=

21. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s

22. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s

23. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s A = ?

24. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no

25. Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no T = 4.6 sec

26. Solution #3 Use Equation #2 A = V 2 - V 1 t

27. Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec

28. Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec A = -3.7 m/s 2

29. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid? V 1 = V 2 = A = D = T =

30. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s

31. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s

32. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no

33. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ?

34. Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ? T = 5.0 sec

35. Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2

36. Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2

37. Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2 D = 35 m

38. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = V 2 = a= d= t=

39. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s

40. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ?

41. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2

42. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m

43. Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m T = no

44. Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad

45. Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad V 2 2 = 16 m/s + 2(4.0m/s 2 )(50m)

46. Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad V 2 2 = 16 m/s + 2(40.0m/s 2 )(50m) V 2 = 26 m/s