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Slideshow 22, Mathematics Mr Richard Sasaki
Vietaβs Formulae Slideshow 22, Mathematics Mr Richard Sasaki
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Objectives Understand how two solutions for a quadratic equation can be written as two simultaneous equations Understand how to use these equations Solve such equations to find solutions for π₯
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Vieta Vieta was a French man. He knew how to factorise an equation π π₯ 2 +ππ₯+π=0 and considered this as π₯ 2 + π π π₯+ π π =0. When we factorise this we getβ¦ π₯β π₯ 1 π₯β π₯ 2 =0 for some two solutions π₯ 1 and π₯ 2 . How do they relate to π π and π π ? π π We know that β π₯ 1 + β π₯ 2 = and β π₯ 1 β β π₯ 2 = π π π₯ 1 + π₯ 2 =β π π Soβ¦ and π₯ 1 β π₯ 2 = π π
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Vietaβs Formulae π₯ 1 + π₯ 2 =β π π and . π₯ 1 β π₯ 2 = π π
In the simple case π₯ 2 +ππ₯+π=0, we getβ¦ π₯ 1 + π₯ 2 =βπ π₯ 1 β π₯ 2 =π Example Solve π₯ 2 β3π₯β10=0 using Vietaβs Formulae. We have π=β3 and π=β10 soβ¦ π₯ 1 + π₯ 2 =3 π₯ 1 π₯ 2 =β10 Now letβs try to find the solutions for π₯ 1 and π₯ 2 by solving the simultaneous equations above!
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Vietaβs Formulae β π₯ 1 + π₯ 2 =3 β‘ π₯ 1 π₯ 2 =β10
π₯ 1 π₯ 2 =β10 It doesnβt matter which Iβll substitute into which. I will substitute β‘ into β . β 10 π₯ 2 β‘ π₯ 1 π₯ 2 =β10 β π₯ 1 = β 10 π₯ 2 + π₯ 2 =3 β π₯ 1 + π₯ 2 =3 β β β10+ π₯ 2 2 =3 π₯ 2 β π₯ 2 2 β3 π₯ 2 β10=0 Iβm back where I started!!
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Vietaβs Formulae Because the formulae are derived from the quadratic anyway, we canβt solve them like that. Vietaβs formulae can only be used to solve quadratics visually! π₯ 1 + π₯ 2 =3 π₯ 1 π₯ 2 =β10 What numbers add together to make 3 and multiply together to make β10? β2 and 5! (Itβs very similar to factorisation.) So the solutions are π₯=β2 and 5.
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Vietaβs Formulae Letβs try another! Example We have π= , π= , soβ¦ 13
We have π= , π= , soβ¦ 13 42 π₯ 1 + π₯ 2 =βπ π₯ 1 + π₯ 2 =β13 β π₯ 1 π₯ 2 =π π₯ 1 π₯ 2 =42 What numbers add together to make β13 and multiply together to make 42? β6 and β7! So the solutions are π₯=β6 and β7.
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Answers - Easy 3 2 β3 2 β1, β2 7 10 β7 10 β2, β5 2 β3 β2 β3 1, β3 β5 6
2, 3 6 9 β6 9 β3 6 β7 β6 β7 β7, 1 10 24 β10 24 β4, β6 β10 25 10 25 5 β2 β35 2 β35 7, β5
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Answers - Hard 14 49 β14 49 β7 β11 β26 11 β26 β2, 13 β13 β14 13 β14
β1, 14 β18 81 18 81 9 β9 β9 Β±3 β17 72 17 72 8, 9 19 70 β19 70 β14,β5 2 β2 β2, 0 β169 β169 Β±13
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Vietaβs Formulae If the numbers are easy, it is a similar process solving equations where πβ 1. π₯ 1 + π₯ 2 =β π π and π₯ 1 β π₯ 2 = π π Example Solve 2π₯ 2 β2π₯β4=0 using Vietaβs Formulae. π=2, π=β2, π=β4, π πβ¦ π₯ 1 + π₯ 2 =β π π π₯ 1 + π₯ 2 =1 β π₯ 1 π₯ 2 = π π π₯ 1 π₯ 2 =β2 What numbers add together to make 1 and multiply together to make β2? β1 and 2! So the solutions are π₯=β1 and 2.
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π₯=4 ππ β1 π₯=3 ππ β1 π₯=3 ππ β4 π₯=β1 π₯=β8 ππ 7 π₯=5 ππ β5
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