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Water Distribution Systems

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1 Water Distribution Systems
11/20/2018 The Islamic University of Gaza Faculty of Engineering Civil Engineering Department Hydraulics - ECIV 3322 Chapter 4 Water Distribution Systems 11/20/2018

2 Introduction To deliver water to individual consumers with appropriate
quality, quantity, and pressure in a community setting requires an extensive system of: Pipes. Storage reservoirs. Pumps. Other related accessories. Distribution system: is used to describe collectively the facilities used to supply water from its source to the point of usage . 11/20/2018

3 Methods of Supplying Water
Depending on the topography relationship between the source of supply and the consumer, water can be transported by: Canals. Tunnels. Pipelines. The most common methods are: Gravity supply Pumped supply Combined supply 11/20/2018

4 so that the desired pressure can be maintained
Gravity Supply The source of supply is at a sufficient elevation above the distribution area (consumers). so that the desired pressure can be maintained HGL or EGL Source (Reservoir) (Consumers) Gravity-Supply System 11/20/2018

5 Advantages of Gravity supply
HGL or EGL Source No energy costs. Simple operation (fewer mechanical parts, independence of power supply, ….) Low maintenance costs. No sudden pressure changes 11/20/2018

6 Pumped Supply  Used whenever:
The source of water is lower than the area to which we need to distribute water to (consumers) The source cannot maintain minimum pressure required.  pumps are used to develop the necessary head (pressure) to distribute water to the consumer and storage reservoirs. HGL or EGL (Consumers) Source (River/Reservoir) Pumped-Supply System 11/20/2018

7 Disadvantages of pumped supply
Complicated operation and maintenance. Dependent on reliable power supply. Precautions have to be taken in order to enable permanent supply: Stock with spare parts Alternative source of power supply …. HGL or EGL (Consumers) Source (River/Reservoir) 11/20/2018

8 Combined Supply (pumped-storage supply)
Both pumps and storage reservoirs are used. This system is usually used in the following cases: 1) When two sources of water are used to supply water: Pumping Source (1) Gravity HGL HGL Pumping station City Source (2) 11/20/2018

9 Combined Supply (Continue)
2) In the pumped system sometimes a storage (elevated) tank is connected to the system. When the water consumption is low, the residual water is pumped to the tank. When the consumption is high the water flows back to the consumer area by gravity. Low consumption High consumption Elevated tank Pumping station Pipeline City Source 11/20/2018

10 Combined Supply (Continue)
3) When the source is lower than the consumer area A tank is constructed above the highest point in the area, Then the water is pumped from the source to the storage tank (reservoir). And the hence the water is distributed from the reservoir by gravity. Pumping HGL Gravity HGL Reservoir Pumping Station City 11/20/2018 Source

11 رجال لا تلهيهم تجارة ولا بيع عن ﺫكر الله
قال الله تعالى: رجال لا تلهيهم تجارة ولا بيع عن ﺫكر الله 11/20/2018

12 Distribution Systems (Network Configurations )
In laying the pipes through the distribution area, the following configuration can be distinguished: Branching system (Tree) Grid system (Looped) Combined system 11/20/2018

13 Branching System (tree system)
Source Submain Main pipe Dead End Branching System Advantages: Simple to design and build. Less expensive than other systems. 11/20/2018

14 Disadvantages: Source Dead End The large number of dead ends which results in sedimentation and bacterial growths. When repairs must be made to an individual line, service connections beyond the point of repair will be without water until the repairs are made. The pressure at the end of the line may become undesirably low as additional extensions are made. 11/20/2018

15 Grid System (Looped system)
Advantages: The grid system overcomes all of the difficulties of the branching system discussed before. No dead ends. (All of the pipes are interconnected). Water can reach a given point of withdrawal from several directions. 11/20/2018

16 Disadvantages: Hydraulically far more complicated than branching system (Determination of the pipe sizes is somewhat more complicated) . Expensive (consists of a large number of loops). But, it is the most reliable and used system. 11/20/2018

17 Combined System It is a combination of both Grid and Branching systems
This type is widely used all over the world. 11/20/2018

18 حب الدنيا اعلم أنّ جمود العين من قسوة القلب،
          جمود العين من قسوة القلب،                 وقسوة القلب من كثرة الذنوب،                         وكثرة الذنوب من نسيان الموت،                                 ونسيان الموت من طول الأمل،                                          وطول الأمل من شدة الحرص،                                                    وشدة الحرص من حب الدنيا،                                                         وحب الدنيا رأس كل خطيئة. 11/20/2018

19 Design of Water Distribution Systems
A properly designed water distribution system should fulfill the following requirements: Main requirements : Satisfied quality and quantity standards Additional requirements : To enable reliable operation during irregular situations (power failure, fires..) To be economically and financially viable, ensuring income for operation, maintenance and extension. To be flexible with respect to the future extensions. 11/20/2018

20 The design of water distribution systems must undergo through different studies and steps:
Design Phases Preliminary Studies Network Layout Hydraulic Analysis 11/20/2018

21 Preliminary Studies: Must be performed before starting the actual design: 4.3.A.1 Topographical Studies: Contour lines (or controlling elevations). Digital maps showing present (and future) houses, streets, lots, and so on.. Location of water sources so to help locating distribution reservoirs. 11/20/2018

22 Water Demand Studies: Water consumption is ordinarily divided into the following categories: Domestic demand. Industrial and Commercial demand. Agricultural demand. Fire demand. Leakage and Losses. 11/20/2018

23 Domestic demand It is the amount of water used for Drinking, Cocking, Gardening, Car Washing, Bathing, Laundry, Dish Washing, and Toilet Flushing. The average water consumption is different from one population to another. In Gaza strip the average consumption is 70 L/capita/day which is very low compared with other countries. For example, it is 250 L/c/day in United States, and it is 180 L/c/day for population live in Cairo (Egypt). The average consumption may increase with the increase in standard of living. The water consumption varies hourly, daily, and monthly 11/20/2018

24 How to predict the increase of population?
The total amount of water for domestic use is a function of: Population increase How to predict the increase of population? Use Geometric-increase model P0 = recent population r = rate of population growth n = design period in years P = population at the end of the design period. The total domestic demand can be estimated using: Qdomestic = Qavg * P 11/20/2018

25 Industrial and Commercial demand
It is the amount of water needed for factories, offices, and stores…. Varies from one city to another and from one country to another Hence should be studied for each case separately. However, it is sometimes taken as a percentage of the domestic demand. 11/20/2018

26 Agricultural demand Fire demand
It depends on the type of crops, soil, climate… Fire demand To resist fire, the network should save a certain amount of water. Many formulas can be used to estimate the amount of water needed for fire. 11/20/2018

27 Fire demand Formulas QF = fire demand l/s P = population in thousands QF = fire demand l/s P = population in thousands QF = fire demand flow m3/d A = areas of all stories of the building under consideration (m2 ) C = constant depending on the type of construction; The above formulas can be replaced with local ones (Amounts of water needed for fire in these formulas are high). 11/20/2018

28 Leakage and Losses This is “ unaccounted for water ”(UFW)
It is attributable to: Errors in meter readings Unauthorized connections Leaks in the distribution system 11/20/2018

29 تهادوا تحابوا لا تبخل بالهدية ولو قلّ سعرها
فقيمتها معنوية اكثر من مادية 11/20/2018

30 Design Criteria Are the design limitations required to get the most efficient and economical water-distribution network Pressure Pipe Sizes Design Period Velocity Head Losses Average Water Consumption 11/20/2018

31 Velocity Not be lower than 0.6 m/s to prevent sedimentation
Not be more than 3 m/s to prevent erosion and high head losses. Commonly used values are m/sec. 11/20/2018

32 Pressure Pressure in municipal distribution systems ranges from kPa in residential districts with structures of four stories or less and kPa in commercial districts. Also, for fire hydrants the pressure should not be less than 150 kPa (15 m of water). In general for any node in the network the pressure should not be less than 25 m of water. Moreover, the maximum pressure should be limited to 70 m of water 11/20/2018

33 Pipe sizes Lines which provide only domestic flow may be as small as 100 mm (4 in) but should not exceed 400 m in length (if dead-ended) or 600 m if connected to the system at both ends. Lines as small as mm (2-3 in) are sometimes used in small communities with length not to exceed 100 m (if dead-ended) or 200 m if connected at both ends. The size of the small distribution mains is seldom less than 150 mm (6 in) with cross mains located at intervals not more than 180 m. In high-value districts the minimum size is 200 mm (8 in) with cross-mains at the same maximum spacing. Major streets are provided with lines not less than 305 mm (12 in) in diameter. 11/20/2018

34 Head Losses Optimum range is 1-4 m/km.
Maximum head loss should not exceed 10 m/km. 11/20/2018

35 Design Period for Water supply Components
The economic design period of the components of a distribution system depends on Their life. First cost. And the ease of expandability. 11/20/2018

36 Average Water Consumption
From the water demand (preliminary) studies, estimate the average and peak water consumption for the area. 11/20/2018

37 Network Layout Next step is to estimate pipe sizes on the basis of water demand and local code requirements. The pipes are then drawn on a digital map (using AutoCAD, for example) starting from the water source. All the components (pipes, valves, fire hydrants) of the water network should be shown on the lines. 11/20/2018

38 Pipe Networks A hydraulic model is useful for examining the impact of design and operation decisions. Simple systems, such as those discussed in last chapters can be solved using a hand calculator. However, more complex systems require more effort even for steady state conditions, but, as in simple systems, the flow and pressure-head distribution through a water distribution system must satisfy the laws of conservation of mass and energy. 11/20/2018

39 Pipe Networks The equations to solve Pipe network must satisfy the following condition: The net flow into any junction must be zero The net head loss a round any closed loop must be zero. The HGL at each junction must have one and only one elevation All head losses must satisfy the Moody and minor-loss friction correlation 11/20/2018

40 Node, Loop, and Pipes Pipe Node Loop 11/20/2018

41 Hydraulic Analysis After completing all preliminary studies and layout drawing of the network, one of the methods of hydraulic analysis is used to Size the pipes and Assign the pressures and velocities required. 11/20/2018

42 Hydraulic Analysis of Water Networks
The solution to the problem is based on the same basic hydraulic principles that govern simple and compound pipes that were discussed previously. The following are the most common methods used to analyze the Grid-system networks: Hardy Cross method. Sections method. Circle method. Computer programs (Epanet,Loop, Alied...) 11/20/2018

43 Hardy Cross Method This method is applicable to closed-loop pipe networks (a complex set of pipes in parallel). It depends on the idea of head balance method Was originally devised by professor Hardy Cross. 11/20/2018

44 Assumptions / Steps of this method:
Assume that the water is withdrawn from nodes only; not directly from pipes. The discharge, Q , entering the system will have (+) value, and the discharge, Q , leaving the system will have (-) value. Usually neglect minor losses since these will be small with respect to those in long pipes, i.e.; Or could be included as equivalent lengths in each pipe. Assume flows for each individual pipe in the network. At any junction (node), as done for pipes in parallel, or 11/20/2018

45 Around any loop in the grid, the sum of head losses must equal to zero:
Conventionally, clockwise flows in a loop are considered (+) and produce positive head losses; counterclockwise flows are then (-) and produce negative head losses. This fact is called the head balance of each loop, and this can be valid only if the assumed Q for each pipe, within the loop, is correct. The probability of initially guessing all flow rates correctly is virtually null. Therefore, to balance the head around each loop, a flow rate correction ( ) for each loop in the network should be computed, and hence some iteration scheme is needed. 11/20/2018

46 After finding the discharge correction, (one for each loop) , the assumed discharges Q0 are adjusted and another iteration is carried out until all corrections (values of ) become zero or negligible. At this point the condition of : is satisfied. Notes: The flows in pipes common to two loops are positive in one loop and negative in the other. When calculated corrections are applied, with careful attention to sign, pipes common to two loops receive both corrections. 11/20/2018

47 How to find the correction value ( )
Neglect terms contains For each loop 11/20/2018

48 If Darcy-Wiesbach is used to find the head losses, then
Note that if Hazen Williams (which is generally used in this method) is used to find the head losses, then (n = 1.85) , then If Darcy-Wiesbach is used to find the head losses, then (n = 2) , then 11/20/2018

49 Example Solve the following pipe network using Hazen William Method CHW =100 1 2 3 4 5 37.8 L/s 25.2 L/s 63 L/s 24 12.6 11.4 39 D L pipe 150mm 305m 1 2 200mm 610m 3 457m 4 153m 5 25.2 11/20/2018

50 1 2 3 4 5 11/20/2018

51 1 2 3 4 5 11/20/2018

52 Example Solve the following pipe network using Hazen William Method CHW =120 11/20/2018

53 Iteration 1 11/20/2018

54 11/20/2018

55 Iteration 2 11/20/2018

56 Iteration 3 11/20/2018

57 Example The figure below represents a simplified pipe network.
Flows for the area have been disaggregated to the nodes, and a major fire flow has been added at node G. The water enters the system at node A. Pipe diameters and lengths are shown on the figure. Find the flow rate of water in each pipe using the Hazen-Williams equation with CHW = 100. Carry out calculations until the corrections are less then 0.2 m3/min. 11/20/2018

58 ”ومن يتق الله يجعل له مخرجاً ويرزقه من حيث لا يحتسب“
تقوى الله مفتاح كل نجاح ”ومن يتق الله يجعل له مخرجاً ويرزقه من حيث لا يحتسب“ 11/20/2018

59 11/20/2018

60 11/20/2018

61 11/20/2018

62 11/20/2018

63 11/20/2018

64 11/20/2018

65 11/20/2018

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67 11/20/2018

68 General Notes Occasionally the assumed direction of flow will be incorrect. In such cases the method will produce corrections larger than the original flow and in subsequent calculations the direction will be reversed. Even when the initial flow assumptions are poor, the convergence will usually be rapid. Only in unusual cases will more than three iterations be necessary. The method is applicable to the design of new system or to evaluation of proposed changes in an existing system. The pressure calculation in the above example assumes points are at equal elevations. If they are not, the elevation difference must be includes in the calculation. The balanced network must then be reviewed to assure that the velocity and pressure criteria are satisfied. If some lines do not meet the suggested criteria, it would be necessary to increase the diameters of these pipes and repeat the calculations. 11/20/2018

69 Summary Assigning clockwise flows and their associated head losses are positive, the procedure is as follows: Assume values of Q to satisfy Q = 0. Calculate HL from Q using hf = K1Q2 . If hf = 0, then the solution is correct. If hf  0, then apply a correction factor, Q, to all Q and repeat from step (2). For practical purposes, the calculation is usually terminated when hf < 0.01 m or Q < 1 L/s. A reasonably efficient value of Q for rapid convergence is given by; 11/20/2018

70 Example The following example contains nodes with different elevations and pressure heads. Neglecting minor loses in the pipes, determine: The flows in the pipes. The pressure heads at the nodes. 11/20/2018

71 Assume T= 150C 11/20/2018

72 Assume flows magnitude and direction
11/20/2018

73 First Iteration Loop (1) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) AB
600 0.25 0.12 0.0157 11.48 95.64 BE 200 0.10 0.01 0.0205 3.38 338.06 EF 0.15 -0.06 0.0171 -40.25 670.77 FA 0.20 -0.10 0.0162 -8.34 83.42 S -33.73 11/20/2018

74 First Iteration Loop (2) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) BC
600 0.15 0.05 0.0173 28.29 565.81 CD 200 0.10 0.01 0.0205 3.38 338.05 DE -0.02 0.0189 -4.94 246.78 EB -0.01 -3.38 S 23.35 1488.7 11/20/2018

75 Second Iteration Loop (1) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) AB
14.20 Second Iteration 14.20 14.20 7.84 Loop (1) 14.20 Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) AB 600 0.25 0.1342 0.0156 14.27 106.08 BE 200 0.10 0.0186 31.48 982.60 EF 0.15 0.0174 -23.89 521.61 FA 0.20 0.0163 -6.21 72.33 S 15.65 11/20/2018

76 Second Iteration Loop (2) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) BC
7.84 14.20 7.84 7.84 Loop (2) 7.84 Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) BC 600 0.15 0.0176 20.37 483.24 CD 200 0.10 0.0261 0.20 93.23 DE 0.0182 -9.22 331.23 EB 0.0186 -31.48 982.60 S -20.13 11/20/2018

77 Third Iteration Loop (1) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) AB
600 0.25 0.1296 0.0156 13.30 102.67 BE 200 0.10 0.0190 15.30 693.08 EF 0.15 0.0173 -28.78 570.54 FA 0.20 0.0163 -6.87 75.97 S -7.05 11/20/2018

78 Third Iteration Loop (2) Pipe L (m) D Q (m3/s) f hf hf/Q (m/m3/s) BC
600 0.15 0.0174 25.61 539.30 CD 200 0.10 0.0212 1.96 262.11 DE 0.0186 -6.17 274.07 EB 0.0190 -15.30 693.08 S 6.1 11/20/2018

79 After applying Third correction
11/20/2018

80 Velocity and Pressure Heads:
pipe Q (l/s) V (m/s) hf (m) AB 131.99 2.689 13.79 BE 26.23 3.340 21.35 FE 48.01 2.717 26.16 AF 88.01 2.801 6.52 BC 45.76 2.589 23.85 CD 5.76 0.733 1.21 ED 24.24 1.372 7.09 13.79 23.85 6.52 21.35 1.21 26.16 7.09 11/20/2018

81 Velocity and Pressure Heads:
Node p/g+Z (m) Z P/g A 70 30 40 B 56.21 25 31.21 C 32.36 20 12.36 D 31.15 11.15 E 37.32 22 15.32 F 63.48 38.48 13.79 23.85 21.35 1.21 6.52 7.09 26.16 11/20/2018

82 Example For the square loop shown, find the discharge in all the pipes. All pipes are 1 km long and 300 mm in diameter, with a friction factor of Assume that minor losses can be neglected. 11/20/2018

83 Solution: Assume values of Q to satisfy continuity equations all at nodes. The head loss is calculated using; HL = K1Q2 HL = hf + hLm But minor losses can be neglected:  hLm = 0 Thus HL = hf Head loss can be calculated using the Darcy-Weisbach equation 11/20/2018

84 Since HL > 0.01 m, then correction has to be applied. Pipe Q (L/s)
First trial Since HL > 0.01 m, then correction has to be applied. Pipe Q (L/s) HL (m) HL/Q AB 60 2.0 0.033 BC 40 0.886 0.0222 CD AD -40 -0.886 2.00 0.0774 11/20/2018

85 Pipe Q (L/s) HL (m) HL/Q Pipe Discharge (L/s)
Second trial Since HL ≈ 0.01 m, then it is OK. Thus, the discharge in each pipe is as follows (to the nearest integer). Pipe Q (L/s) HL (m) HL/Q AB 47.08 1.23 0.0261 BC 27.08 0.407 0.015 CD -12.92 -0.092 0.007 AD -52.92 -1.555 0.0294 Pipe Discharge (L/s) AB 47 BC 27 CD -13 AD -53 11/20/2018


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