1. ADINA INSTITUTE OF SCIENCE AND TECHNOLOGY

2. Ques. From top of a tower , 60m high a bullet is fired
Ques. From top of a tower , 60m high a bullet is fired at an angle of 20 degree up the horizontal with velocity 120m/sec. Determine
Time of flight
Horizontal range of ground
Maximum height of the bullet from the ground.

3. FORMULA USED Time of flight t = 2VoSinϴ
Horizontal range of ground R = Vicosϴt
v = u+at

4. Given Vo = 120 m/sec
g = 9.8 m/ sec
= 20 degree
Time of flight = 2VoSinϴ /g
= (2*120*sin20)/9.8
= 8.378
= 8.38 sec.

5. ii) Horizontal range of ground R = ViCosϴ. t = 120. cos20. 8. 38 = 120
ii) Horizontal range of ground R = ViCosϴ*t = 120*cos20*8.38 = 120*0.939*8.38 = meters.

6. iii) tanϴ= P/B P = B. tanϴ = 472. tan20 = 171
iii) tanϴ= P/B P = B*tanϴ = 472*tan20 = Therefore , height of the bullet from the ground = = m.