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© University of Wisconsin, CS559 Spring 2004
Last Time Subdivision Sphere Fractals Modified Butterfly scheme 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Today Parametric curves Hermite curves Bezier curves Homework 6 due Homework 7 available Friday, due May 4 No lecture April 22 (Thursday) 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Subdivision Shortcomings
Subdivision surfaces suffer from parameterization problems How are texture coordinates handled? Surface are 2D in nature, how do we attached a 2D space to subdivision surfaces? Subdivision surfaces can be difficult to model with Still may take complex underlying surface to get desired shape Effects of changes to underlying mesh are not always obvious Evaluation is non-trivial Methods exist for taking a point in the underlying mesh and figuring out where it will go on the surface, but it isn’t easy 4/20/04 © University of Wisconsin, CS559 Spring 2004
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What are Parametric Curves?
Define a parameter space 1D for curves 2D for surfaces Define a mapping from parameter space to 3D points A function that takes parameter values and gives back 3D points The result is a parametric curve or surface (Fx(t), Fy(t)) Mapping:F:t→(x,y) 1 1 t 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Why Parametric Curves? Parametric curves are intended to provide the generality of polygon meshes but with fewer parameters for smooth surfaces Polygon meshes have as many parameters as there are vertices (at least) Fewer parameters makes it faster to create a curve, and easier to edit an existing curve Normal vectors and texture coordinates can be easily defined everywhere Parametric curves are easier to animate than polygon meshes 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Parametric Curves We have seen the parametric form for a line: Note that x, y and z are each given by an equation that involves: The parameter t Some user specified control points, x0 and x1 This is an example of a parametric curve 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Basis Functions (first sighting)
A line is the sum of two functions multiplied by vectors: A linear combination of basis functions t and 1-t are the basis functions The weights are called control points (x0,y0,z0) and (x1,y1,z1) are the control points They control the shape and position of the curve 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Hermite Spline A spline is a parametric curve defined by control points The term spline dates from engineering drawing, where a spline was a piece of flexible wood used to draw smooth curves The control points are adjusted by the user to control the shape of the curve A Hermite spline is a curve for which the user provides: The endpoints of the curve The parametric derivatives of the curve at the endpoints (tangents with length) The parametric derivatives are dx/dt, dy/dt, dz/dt That is enough to define a cubic Hermite spline 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Control Point Interpretation
End Tangent Start Tangent End Point Start Point 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Hermite Spline (2) Say the user provides A cubic spline has degree 3, and is of the form: For some constants a, b, c and d derived from the control points, but how? We have constraints: The curve must pass through x0 when t=0 The derivative must be x’0 when t=0 The curve must pass through x1 when t=1 The derivative must be x’1 when t=1 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Hermite Spline (3) Solving for the unknowns gives: Rearranging gives: or 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Basis Functions A point on a Hermite curve is obtained by multiplying each control point by some function and summing 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Splines in 2D and 3D For higher dimensions, define the control points in higher dimensions (that is, as vectors) 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Bezier Curves (1) Different choices of basis functions give different curves Choice of basis determines how the control points influence the curve In Hermite case, two control points define endpoints, and two more define parametric derivatives For Bezier curves, two control points define endpoints, and two control the tangents at the endpoints in a geometric way 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Control Point Interpretation
Point along start tangent End Point Point along end Tangent Start Point 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Bezier Curves (2) The user supplies d control points, pi Write the curve as: The functions Bid are the Bernstein polynomials of degree d Where else have you seen them? This equation can be written as a matrix equation also There is a matrix to take Hermite control points to Bezier control points 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Bezier Basis Functions for d=3
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Bezier Curves of Varying Degree
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Bezier Curve Properties
The first and last control points are interpolated The tangent to the curve at the first control point is along the line joining the first and second control points The tangent at the last control point is along the line joining the second last and last control points The curve lies entirely within the convex hull of its control points The Bernstein polynomials (the basis functions) sum to 1 and are everywhere positive They can be rendered in many ways E.g.: Convert to line segments with a subdivision algorithm 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Rendering Bezier Curves (1)
Evaluate the curve at a fixed set of parameter values and join the points with straight lines Advantage: Very simple Disadvantages: Expensive to evaluate the curve at many points No easy way of knowing how fine to sample points, and maybe sampling rate must be different along curve No easy way to adapt. In particular, it is hard to measure the deviation of a line segment from the exact curve 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Rendering Bezier Curves (2)
Recall that a Bezier curve lies entirely within the convex hull of its control vertices If the control vertices are nearly collinear, then the convex hull is a good approximation to the curve Also, a cubic Bezier curve can be broken into two shorter cubic Bezier curves that exactly cover the original curve This suggests a rendering algorithm: Keep breaking the curve into sub-curves Stop when the control points of each sub-curve are nearly collinear Draw the control polygon - the polygon formed by the control points 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Sub-Dividing Bezier Curves
Step 1: Find the midpoints of the lines joining the original control vertices. Call them M01, M12, M23 Step 2: Find the midpoints of the lines joining M01, M12 and M12, M23. Call them M012, M123 Step 3: Find the midpoint of the line joining M012, M123. Call it M0123 The curve with control points P0, M01, M012 and M0123 exactly follows the original curve from the point with t=0 to the point with t=0.5 The curve with control points M0123 , M123 , M23 and P3 exactly follows the original curve from the point with t=0.5 to the point with t=1 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Sub-Dividing Bezier Curves
M12 P1 P2 M012 M0123 M123 M01 M23 P0 P3 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Sub-Dividing Bezier Curves
P1 P2 P0 P3 4/20/04 © University of Wisconsin, CS559 Spring 2004
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de Casteljau’s Algorithm
You can find the point on a Bezier curve for any parameter value t with a similar algorithm Say you want t=0.25, instead of taking midpoints take points 0.25 of the way M12 P2 P1 M23 t=0.25 M01 P0 P3 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Invariance Translational invariance means that translating the control points and then evaluating the curve is the same as evaluating and then translating the curve Rotational invariance means that rotating the control points and then evaluating the curve is the same as evaluating and then rotating the curve These properties are essential for parametric curves used in graphics It is easy to prove that Bezier curves, Hermite curves and everything else we will study are translation and rotation invariant Some forms of curves, rational splines, are also perspective invariant Can do perspective transform of control points and then evaluate the curve 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Longer Curves A single cubic Bezier or Hermite curve can only capture a small class of curves At most 2 inflection points One solution is to raise the degree Allows more control, at the expense of more control points and higher degree polynomials Control is not local, one control point influences entire curve Alternate, most common solution is to join pieces of cubic curve together into piecewise cubic curves Total curve can be broken into pieces, each of which is cubic Local control: Each control point only influences a limited part of the curve Interaction and design is much easier 4/20/04 © University of Wisconsin, CS559 Spring 2004
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Piecewise Bezier Curve
“knot” P0,0 P1,3 P0,3 P1,0 P1,2 P1,1 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Continuity When two curves are joined, we typically want some degree of continuity across the boundary (the knot) C0, “C-zero”, point-wise continuous, curves share the same point where they join C1, “C-one”, continuous derivatives, curves share the same parametric derivatives where they join C2, “C-two”, continuous second derivatives, curves share the same parametric second derivatives where they join Higher orders possible Question: How do we ensure that two Hermite curves are C1 across a knot? Question: How do we ensure that two Bezier curves are C0, or C1, or C2 across a knot? 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Achieving Continuity For Hermite curves, the user specifies the derivatives, so C1 is achieved simply by sharing points and derivatives across the knot For Bezier curves: They interpolate their endpoints, so C0 is achieved by sharing control points The parametric derivative is a constant multiple of the vector joining the first/last 2 control points So C1 is achieved by setting P0,3=P1,0=J, and making P0,2 and J and P1,1 collinear, with J-P0,2=P1,1-J C2 comes from further constraints on P0,1 and P1,2 4/20/04 © University of Wisconsin, CS559 Spring 2004
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© University of Wisconsin, CS559 Spring 2004
Bezier Continuity P0,1 P0,2 P0,0 P1,3 J P1,2 P1,1 Disclaimer: PowerPoint curves are not Bezier curves, they are interpolating piecewise quadratic curves! This diagram is an approximation. 4/20/04 © University of Wisconsin, CS559 Spring 2004
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