Download presentation
Presentation is loading. Please wait.
1
Quantum Foundations Lecture 15
April 2, 2018 Dr. Matthew Leifer HSC112
2
Announcements Schmid College Academic Advising:
Tuesday April 3, 4:30pm-6:30pm AF209A (Prof. Leifer) Wednesday April 4, 4:30pm-6:30pm Henley Hall Basement (Prof. Dressel) Adam Becker is returning to Chapman: Book event and signing at 1888 center: Monday April 16. RSVP required Assignments First Draft due on Blackboard April 11. Peer review until April 16. Discussion in class April 16. Final Version due May 2. Homework 3 due April 11. I like lunch invitations
3
Application: Minimum Error Discrimination
Alice has a preparation device that prepares the system in either the state π or the state π. She chooses each with 50/50 probability and sends the system to Bob. Bob makes a measurement on the system and has to guess whether π or π was prepared. What is his maximum probability of success and what measurement should he make?
4
Classical Case Letβs look at the classical case first. There is a variable that can take π possible values π=1,2,β―,π. Alice prepares the probability distributions π or π with 50/50 probability. Bob sees the value of π and has to guess whether π or π was prepared. Bob decides on a subset πΈ π β{1,2,β―,π}. If πβ πΈ π he guesses π. If it is in the complement πΈ π = 1,2,β―,π \ πΈ π , he guesses π.
5
Classical Case Therefore,
π succ β€ {π| π π β₯ π π } ( π π β π π ) = {π| π π β₯ π π } ( π π β π π ) + {π| π π < π π } ( π π β π π ) = π=1 π π π β π π = π· π (π,π) Where π· π π,π = 1 2 π=1 π π π β π π is called the variational distance.
6
Quantum Case Theorem (Helstrom, Holevo): The optimal success probability in the quantum case is given by π succ = π· π (π,π) where π· π π,π = 1 2 Tr πβπ is known as the trace distance, and the matrix norm is given by π = π β π .
7
π = π β π = π 2 because π is Hermitian.
Quantum Case Lemma: If π is a Hermitian operator then Tr π = π | π π | where π π are the eigenvalues of π. Proof: Let π= π π π | π π β©β¨ π π | be the spectral decomposition of π and write π= {π| π π β₯0} π π | π π β©β¨ π π | β {π| π π <0} π π | π π β©β¨ π π | Then, π = π β π = π 2 because π is Hermitian.
8
Quantum Case π = π 2 = {π| π π β₯0} π π | π π β©β¨ π π | β {π| π π <0} π π | π π β©β¨ π π | {π| π π β₯0} π π | π π β©β¨ π π | β {π |π π <0} π π | π π β©β¨ π π | = {π| π π β₯0} {π| π π β₯0} π π π π π π π π π π β©β¨ π π | + {π| π π <0} {π| π π <0} π π π π π π π π π π β©β¨ π π | Note: cross terms are zero because the subspaces with π π β₯0 and π π <0 are orthogonal. π = {π| π π β₯0} {π| π π β₯0} π π π π πΏ ππ π π β¨ π π | + {π| π π <0} {π| π π <0} π π π π πΏ ππ π π β¨ π π | = {π| π π β₯0} π π π π π π + {π| π π <0} π π π π π π = π π π π π π π = π π π π π π π And hence Tr π = π | π π | .
9
Quantum Case Now consider Bobβs strategy. He has to choose a two-outcome POVM: πΈ π , πΈ π =πΌβ πΈ π , such that if he gets the outcome πΈ π he will guess π and if he gets the outcome πΈ π he will guess π. His success probability is π succ =Prob π is prepared Prob( πΈ π |π)+Prob π is prepared Prob( πΈ π |π) = 1 2 Tr πΈ π π +Tr( πΈ π π) = 1 2 Tr πΈ π π +Tr πΌβ πΈ π π = 1 2 Tr π +Tr πΈ π (πβπ) = Tr πΈ π (πβπ)
10
πΈ π = π + = {π| π π β₯0} | π π β©β¨ π π |
Quantum Case Now let πβπ= π π π π π π π be the spectral decomposition of πβπ. Tr πΈ π (πβπ) =Tr πΈ π π π π π π π π = π π π Tr πΈ π | π π β©β¨ π π | = π π π β¨ π π | πΈ π | π π β© Now, 0β€ π π πΈ π π π β€1, so this is clearly maximized if we can choose π π πΈ π π π =1 for π π β₯0 and π π πΈ π π π =0 for π π <0. This can be achieved if we choose πΈ π = π + = {π| π π β₯0} | π π β©β¨ π π |
11
Quantum Case So we have Tr πΈ π (πβπ) β€Tr π + (πβπ)
= π π π β¨ π π | π + | π π β© = π {π| π π β₯0} π π β¨ π π | π π β©β¨ π π | π π β© = {π| π π β₯0} | π π | However, π and π are both density matrices, so Tr πβπ =Tr π βTr π =1β1=0 Therefore π π π = {π| π π β₯0} | π π | β {π| π π <0} | π π | =0 or {π| π π β₯0} | π π | = {π| π π <0} | π π |
12
Quantum Case Hence, {π| π π β₯0} | π π | = {π| π π β₯0} | π π | + {π| π π <0} | π π | = 1 2 π | π π | Now, if we apply the lemma, this gives {π| π π β₯0} | π π | = 1 2 Tr πβπ = π· π (π,π) Putting it all together gives π succ β€ π· π (π,π) with equality achieved if Bob chooses πΈ π = π + , i.e. the projector onto the positive eigenspace of πβπ.
13
π= π π π |πβ©β¨π| and π= π π π |πβ©β¨π|
Special Cases Note that if π and π are diagonal in the same basis π= π π π |πβ©β¨π| and π= π π π |πβ©β¨π| then the eigenvalues of πβπ are π π β π π and we get π· π π,π = 1 2 π π π β π π = π· π (π,π) recovering the classical result. If π=|πβ©β¨π| and π=|πβ©β¨π| are both pure states then (you will prove on Hwk. 4) π· π π,π = 1β π π 2 Therefore, pure states are perfectly distinguishable iff π π =0.
14
8.vi) The Lindblad Equation
15
Continuous Time Dynamics
16
The View from the Larger Church
17
The View from the Larger Church
18
Deriving the Lindblad Equation
19
Deriving the Lindblad Equation
20
Deriving the Lindblad Equation
21
Example: Decoherence
22
9) Ontological Models The aim of this section is to investigate the possibility of constructing a realist theory (known as an ontological model) that can reproduce the predictions of quantum theory. We start with a simple toy-model that reproduces many of the apparently puzzling phenomena we have studied so far: The Spekkensβ toy theory. These phenomena are naturally explained if there is a restriction on the amount of information we can have about the ontic state (an βepistemic restrictionβ or βepistrictionβ) and the quantum state is epistemic. After this we will present the general definition of an ontological model and prove a number of no-go theorems that imply that a realist theory underlying quantum theory cannot be like this.
23
9) Ontological Models Good references for this section include:
David Jennings and Matthew Leifer, βNo Return to Classical Realityβ, Contemporary Physics, vol. 57, iss. 1, pp (2015) preprint: Robert W. Spekkens, βQuasi-Quantization: Classical Statistical Theories with an Epistemic Restrictionβ, in βQuantum Theory: Informational Foundations and Foilsβ, Giulio Chiribella and Robert W. Spekkens (eds.), pp , Springer (2015) preprint: Robert W. Spekkens, βContextuality for preparations, transformations, and unsharp measurementsβ, Physical Review A, vol (2005). Preprint: J. S. Bell, βSpeakable and Unspeakable in Quantum Mechanicsβ, 2nd edition, Cambridge University Press (2004). Matthew Leifer, βIs the Quantum State Real? An Extended Review of Ο-ontology Theoremsβ, Quanta, vol. 3, no. 1, pp (2014).
24
9) Ontological Models Ontological Models Epistricted Theories
Definitions Examples Excess Baggage Contextuality Ξ¨-ontology Bellβs Theorem The Colbeck-Renner Theorem
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.