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Probability.

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Presentation on theme: "Probability."β€” Presentation transcript:

1 Probability

2 Some fundamentals 𝑨 2 4 6 3 5 1 𝑩 𝑺 𝑆= the whole sample space (1 to 6) 𝐴= even number on a die thrown 𝐡= prime number on a die thrown What does it mean in this context? What is the resulting set of outcomes? 𝐴′ ? Not A. i.e. Not rolling an even number. ? {1, 3, 5} 𝐴βˆͺ𝐡 ? A or B. i.e. Rolling an even or prime number. ? {2,3,4,5,6} 𝐴∩𝐡 ? A and B. i.e. Rolling a number which is even and prime. ? {2}

3 Some fundamentals 𝑨 2 4 6 3 5 1 𝑩 𝑺 𝑆= the whole sample space (1 to 6) 𝐴= even number on a die thrown 𝐡= prime number on a die thrown What does it mean in this context? What is the resulting set of outcomes? π΄βˆ©π΅β€² ? Rolling a number which is even and not prime. ? {4,6} (𝐴βˆͺ𝐡)β€² ? Rolling a number which is not [even or prime]. ? {1} 𝐴∩𝐡 β€² ? Rolling a number which is not [even and prime]. ? {1,3,4,5,6}

4 What area is indicated? A C B S 𝐴∩𝐡 ?

5 What area is indicated? A C B S 𝐴βˆͺ𝐡 ?

6 What area is indicated? A C B S 𝐴∩𝐡∩𝐢 ?

7 What area is indicated? A C B S 𝐴∩ 𝐢 β€² ?

8 What area is indicated? A C B S 𝐴∩𝐡∩ 𝐢 β€² ?

9 A C B S 𝐴 β€² ∩ 𝐡 β€² ∩ 𝐢 β€² 𝐴βˆͺ𝐡βˆͺ𝐢 β€² What area is indicated? ? ? or
alternatively… ? 𝐴βˆͺ𝐡βˆͺ𝐢 β€²

10 What area is indicated? A C B S 𝐴 β€² ?

11 What area is indicated? A C B S 𝐴∩ 𝐡∩𝐢 β€² ?

12 What area is indicated? A C B S 𝐴∩ 𝐡 β€² βˆ©πΆβ€² ?

13 Test Your Understanding
? 𝑆 𝐡 𝐴 0.33 0.32 0.3 0.05 Given that 𝑃 𝐴 β€² ∩𝐡 =0.3 and 𝑃 [𝐴βˆͺ𝐡]β€² =0.05 and 𝑃 𝐡 =0.62, determine: (using a suitable Venn Diagram) 𝑃 𝐴 =𝟎.πŸ”πŸ“ 𝑃 𝐴∩𝐡 =𝟎.πŸ‘πŸ 𝑃 π΄βˆ©π΅β€² =𝟎.πŸ‘πŸ‘ 𝑃 𝐴βˆͺ𝐡 =𝟎.πŸ—πŸ“ ? a b ? c ? d ?

14 Probability Formulae from the Venn Diagram – The Addition Rule
A and B are two events such that P(A) = 0.6, P(B) = 0.7 and P(A or B) = 0.9. Calculate: a) b) c) d) a) S A B 0.2 0.4 0.3 0.1 Now you know the intersection, you can draw a Venn diagram! 5C

15 Probability Formulae from the Venn Diagram – The Addition Rule
A and B are two events such that P(A) = 0.6, P(B) = 0.7 and P(A or B) = 0.9. Calculate: b) c) d) b) S A B 0.2 0.4 0.3 β€˜Probability of not A’ 0.1 β€˜Probability of not A, or B’ β€˜Probability of not A, and B’ 5C

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