1. Net Ionic Equations
For precipitates only

2. Double Replacement Reactions
A double replacement reaction is when there is an exchange of ions between two compounds.
AX + BY  AY + BX
To tell if it is a double replacement reaction, there are two compounds reacting with each other forming two different compounds
Like “Wife Swap”

3. DR-precipitate review

4. DR-#1 forming precipitate
A solid is formed in a DR when the product is not soluble in water
2NaOH(aq) +2CuCl2(aq)  NaCl(aq) + Cu(OH)2(s)
Write the skeleton, then balance the equation, then look at the solubility chart for states of matter to see if there is a reaction making a solid, gas, water or NR (aq and aq).

5. Steps of Net Ionic
Write the complete molecular equation
Write the complete ionic equation
Identify the spectators (cross out)
Write the net ionic equation

6. Complete molecular equation
2NaOH(aq) + CuCl2(aq)  2NaCl(aq) + Cu(OH)2(s)

7. 2. Complete Ionic Equation
2NaOH(aq) + CuCl2(aq)  2NaCl(aq) + Cu(OH)2(s)
If substance is aqueous and a strong electrolyte we break it apart into its ions.
2Na+ (aq) + 2OH- (aq) + Cu2+ (aq) + 2Cl- (aq)  2Na+ (aq) + 2Cl- (aq) + Cu(OH)2(s)

8. 3. Identify Spectator Ions
2NaOH(aq) + CuCl2(aq)  2NaCl(aq) + Cu(OH)2(s)
We will identify identical ions that are on the left and the right side that are called “spectator ions”
2Na+ (aq) + 2OH+ (aq) + Cu2+ (aq) + 2Cl- (aq)  2Na+ (aq) + 2Cl- (aq) + Cu(OH)2(s)

9. 4. Net Ionic Equation
2NaOH(aq) + CuCl2(aq)  2NaCl(aq) + Cu(OH)2(s)
We will leave only those that are not “spectator ions” for our net ionic equation
2OH+ (aq) + Cu2+ (aq)  Cu(OH)2(s)