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You will need a partner as well as a calculator
The Gas Laws You will need a partner as well as a calculator
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Ideal Gas Law PV = nRT Boyle’s Law P1V1 = P2V2 Combined Gas Law P1V1/T1 = P2V2/T2
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Pressure Pressure (P): The force of gas molecules as they hit the sides of the container in which they are placed. Units = Atmospheres (atm) StandardTemperaturePressure = 1atm
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Temperature StandardTemperaturePressure = 273 K
Temperature (T): Average kinetic energy. The higher the energy, the higher the temperature. Common units of temperature: Kelvin (K): The ONLY units that can be used when doing numerical problems with gases. *Degrees Celsius (0C): Must be converted to Kelvin before doing problems (by adding 273). StandardTemperaturePressure = 273 K
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Volume Volume (V): The amount of space in which a gas is enclosed.
The most commonly used unit of volume is liters (L). Conversion: 1L = 1,000 mL
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Which tank contains the greatest number of particles?
Number of particles = pressure x volume 10 atm 1 atm 40 atm 25 atm 30 L 60 L 45 L 15 L A B C D
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Ideal Gas Law Avogadro’s law: One mole of every gas has the same volume. (22.4 L) STP = standard temperature & pressure Standard temperature = 273 K Standard pressure = 1 atm All gases behave the same at the same temperature, volume and pressure. H2O(g), CO2(g), O2
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Ideal gas law: PV = nRT P = pressure (in atm) V = volume (L)
n = number of (moles) R = ideal gas constant L•atm/mol•K T = temperature (Kelvin) = (oC + 273)
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“We Do” PV = nRT If I have 10 liters of a gas at a pressure of 1.5 atm and a temperature of 250 C, how many moles of gas do I have? P = ___ atm V = ___ L n = ___ mol R = (always this #) ______ atm L/mol K T = __oC + (273) = ___ K
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PV=nRT (P x V) = (n x R x T) 1.5 x 10 = n x 0.0821 x 298
Divide both sides by so “n” by itself n = moles
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“You Do” If I have 23.5 moles of gas at a temperature of oC, and a volume of liters, what is the pressure of gas? P = V = n = R = (always this #) T = ___oC+ (273) =
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Boyle’s Law P1V1 = P2V2 P1 = First Pressure V1 = First Volume
P2 = Second Pressure V2 = Second Volume P and V are inversely proportional (when one increases, the other decreases)
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Boyles’ Law and Breathing
During an inhalation, Lung volume increases. the pressure in the lungs decreases. air flows towards the lower pressure in the lungs. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings
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Boyles’ Law and Breathing
During an exhalation, Lung volume decreases. pressure within the lungs increases. air flows from the higher pressure in the lungs to the outside. Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings
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“We Do” P1V1 = P2V2 A high-altitude balloon contains L of He at 10.3 atm. What is the new volume when the balloon rises to an altitude where the pressure is only 2.3 atm? P1 = V1 = P2 = V2 =
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P1V1 = P2V2 (10.3 atm) (30.0 L) = (2.3 atm) ( V2)
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“You Do” P1V1 = P2V2 A gas with a volume of 4.02 L at a pressure of 2.31 atm is allowed to expand to L. What is the new pressure of the gas? P1 = V1 = P2 = V2 =
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Combined Gas Law P1V1 = P2V2 T1 T2 P1 = First Pressure
****Remember that temperature needs to be in Kelvin (oC = 273K)**** P1 = First Pressure V1 = First Volume T1 = First Temperature P2 = Second Pressure V2 = Second Volume T2 = Second Temperature
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“We Do” P1V1/T1 = P2V2/T2 If I initially have a gas at a pressure of 1.3 atm, a volume of 24.6 liters and a temperature of 214K, and then I raise the volume to 46.0 L and increase the temperature to 286 K, what is the new pressure of the gas? P1 = P2 = V1 = V2 = T1 = T2 =
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P1V1/T1 = P2V2/T2 (1.5 atm)(24.6 L) = (P2)(46.0 L) 214 K 286 K
0.172 atm L/K = (P2) (0.161 atm/K) P2 = 1.75 atm
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“You Do” P1V1/T1 = P2V2/T2 If I have 23.5 L of gas held at STP, what is the volume of gas if I increase the pressure to 45.2 atm and increase the temperature to oC? P1 = P2 = V1 = V2 = T1 = T2 =
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