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Slideshow 10, Mr Richard Sasaki, Mathematics
Conjugations in Surds Slideshow 10, Mr Richard Sasaki, Mathematics
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Objectives Be able to rationalise denominators of fractions in the form π +π Do the same for denominators in the form π π +π Simplify expressions with surds in this form
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Rationalising the Denominator
Previously, we learned how to make the denominator an integer on a fraction. 1β β 2 = 2 2 = If the denominator is in the form π π , we can multiply the top and bottom by π as π π β π =ππ. How about denominators in the form π +π? We need to make a conjugation. Whatβs that?
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Conjugation In maths (not English), a conjugation refers to things that link to one another (a relationship). The conjugate of π +π is . π βπ Example Simplify = β 2 β1 2 β1 = 2 β β 1 2 = 2 β1 2β1 = 2 β1
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Conjugation Example Simplify 3 2 5 β2 . 3 2 5 β2 =
β2 = β2 β = 3 2 β( 5 +2) β 2 2 = β4 =
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2 β3 5 +2 3 +1 3 β1 2 5 +2 β2 2 β3 β 3 +3 4 β5 3 β3 11 β54 7 β42 37 6 6 β12 β7 10 β β18 223 β β600 19
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Answers β Part 1, Hard 12β6 2 4 2 β2 6 5 +2 30β5 2 17 3β 3 2 18 2 β18
12β6 2 4 2 β2 6 5 +2 30β 3β 3 2 18 2 β18 4 10 21 β6 5 4 15 β β 2 +2
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Other Types When we need to conjugate a denominator in the form π π +π, we multiply the numerator and denominator by π π βπ Example Simplify β5 . β5 = β5 β = = 3 5 β( ) β 5 2 = β25 = β6 15 β
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Answers β Part 2, Easy 3 2 +1 9 3 β5 5 7 β2 3 2 +4 2 5 3 β2 71
9 3 β5 5 7 β2 5 3 β2 71 β β 6 β 18β β2 7 β1 27
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3 + 2 7 β 5 2 3 β3 2 4 2 β 3 42 β14 13 3 β 2 6 +3 β β
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