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Core 4 OCR How does the day go?
Session 1 – Algebra Session 2 – Differentiation and Integration 1 Session 3 – Integration 2 and differential equations Session 4 – Vectors If you would like copies of the Powerpoints please visit the Resources page on my website
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Algebra - What you need to know
How to simplify algebraic fractions How to divide a polynomial by a linear or quadratic expression How to write a fraction as the sum of partial fractions How to expand a bracket using the Binomial Expansion for any power How to write a curve given parametrically as the Cartesian equation.
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Algebraic division – boxes method
You may be good at this – keep doing the way you know If this is causing you problems, this tabular method might help you
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Working with cubics Write the x -2 on the outside and the first term on the inside x 2x3 -2 Fill in the first column
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Working with cubics How many more x2 do we need? 2x2 x 2x3 -2 -4x2
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Working with cubics Finish off the table writing an extra number in a box to the right for the remainder 2x2 x 2x3 7x2 -2 -4x2
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Working with cubics 2x2 7x +7 x 2x3 7x2 -2 -4x2 -14x -14 18
Quotient is 2x2 +7x +7 and remainder 18 WARNING: DON’T use this method if the question says “use the remainder theorem” to find the remainder. You’ll get NO MARKS!
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2.Simplifying algebraic fractions Cancel factors in the top with factors in the bottom
(June 08 q1) (a) Simplify
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2b Dividing by quadratics Divide by .
x x2 x3 4x +1
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2b Dividing by quadratics Divide by .
x x2 x3 4x 4x2 +1
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Dividing by quadratics Divide by .
x x2 x3 -2x2 4x 4x2 +1
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2b Dividing by quadratics Divide by .
x -2 x2 x3 -2x2 4x 4x2 +1
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Dividing by quadratics Divide by .
x -2 x2 x3 -2x2 4x 4x2 -8x +1
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2b Dividing by quadratics Divide by .
x -2 x2 x3 -2x2 4x 4x2 -8x +1 x - 3 Quotient is x – 2 and remainder x – 3
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3. A trickier example When is divided by the quotient is and the remainder is Find the values of the constants a, b and c
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Rewriting in terms of multiplication Constant term (or substituting x=0) Cubic term Linear term Quadratic term can be used as a check
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Partial fractions Look at the denominator (bottom) to know how to begin Partial fractions for distinct linear factors (could be two or three) Partial fractions with a repeated factor
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Distinct linear factors
4 Express x in partial fractions ( x – 2 ) ( x - 3 ) x = A + B ( x – 2 ) ( x - 3 ) ( x – 2 ) (x - 3 ) Multiply by denominator… x = A ( x – 3 ) + B (x – 2) Substitute x = 3 to ‘remove’ A = B Substitute x = 2 to ‘remove’ B = -A, A = -2 x = ( x – 2 ) ( x - 3 ) ( x – 2 ) (x - 3 )
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5 Repeated factor x – 1 = A + B + C
( x + 1 ) ( x - 2 ) ( x + 1 ) (x - 2 ) (x - 2 )2 Multiply by denominator x – = A ( x - 2 ) B ( x + 1 )( x - 2 ) C ( x + 1 ) Substitute x = -1 = A B C 0 A = /9 Substitute x = 2 C = 1/3
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x – 1 = A ( x - 2 )2 + B ( x + 1 )( x - 2 ) + C ( x + 1 )
Equate the x2 coefficients 0 = A B B = 2/9 x – = / / / 3 ( x + 1 ) ( x - 2 ) ( x + 1 ) (x - 2 ) (x - 2 )2 Now rewrite x – = ( x + 1 ) ( x - 2 ) ( x + 1 ) (x - 2 ) (x - 2 )2
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Binomial expansion How to expand (1 + x ) to a power
Positive whole number for C1 Negative or fraction power for C4 The expansion is infinite and only valid for |x|<1
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Example 6 The expansion is infinite and only valid for |x|<1
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Approximation We use the first part of the expansion as an approximation for small values of x This could be called a quadratic approximation – but how good is it?
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Look at the graphs
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Look at quadratic and cubic approximations
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What happens if the number is not 1? Example 7
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Example 6 Find a quadratic approximation for
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Putting it all together – Example 8
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Using graphs to check
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Parametric equations A curve is given parametrically when both x and y are given in terms of a third variable, often t or θ
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Eliminating the parameter Example 10
Find the Cartesian equation of the curve given parametrically by
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A tricky one – Example 11 Find the Cartesian equation of the curve given by
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