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Warmup Mg(s) + 2 HCl(g)  MgCl2 (aq) + H2 (g))

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Presentation on theme: "Warmup Mg(s) + 2 HCl(g)  MgCl2 (aq) + H2 (g))"— Presentation transcript:

1 Warmup Mg(s) + 2 HCl(g)  MgCl2 (aq) + H2 (g))
1. Determine the partial pressure of the hydrogen gas, PH2. 2. Determine the volume of the H2 gas at standard temperature and pressure. 3. Determine the mass of the magnesium ribbon; convert this to moles of Mg. 4. From your answers to #2 and #3, determine the volume of a mole of H2 gas.

2 Another way to count particles
Molar Volume Another way to count particles

3 Avogadro’s Hypothesis
You may recall: Under similar conditions of pressure and temperature, equal volumes of gases contain equal numbers of particles Doesn’t matter what gas That means one mole of any gas will occupy a specific volume regardless of the gas (ideally)

4 Molar volume Molar STP=22.4 L (22.4 dm3) 1 mol=22.4 STP

5 Ideal Gas Law At STP 1 mol=22.4 dm3 What about
n mol? So, at STP, n moles=n(22.4 dm3)

6 Ideal Gas Law Based on the Combined Gas Law Ideal Gas Constant, R
P1=101.3 kPa V1=n(22.4 dm3/mol) T1=273 K P2=P V2=V T2=T Ideal Gas Constant, R

7 R depends on units

8 Ex: How many moles of hydrogen will occupy 0
Ex: How many moles of hydrogen will occupy 0.90 dm3 at a pressure of 105 kPa and a temperature of -73°C? V=0.90 dm3 P=105 kPa T=-73°C +273 200K R=8.31 kPa*dm3 mol*K n=?

9 Assignment Unit 9 WS #2


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