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Linear Equations Notes & Practice.

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Presentation on theme: "Linear Equations Notes & Practice."— Presentation transcript:

1 Linear Equations Notes & Practice

2 Things to remember An equation = a statement in algebra that says 2 expressions are equivalent Variables in linear equations only have power of 1 You must balance each side at all times (What you do to one side MUST be done to the other side!).

3 How to approach them If equation has fractions, but the answers don’t, try clearing the fractions in the equation by multiplying by the least common denominator The presence of fractions in the answer choices likely means you’ll need to rely on techniques for combining and simplifying fractions to get to the right answer Seeing decimals in the answer choices likely indicates that using your calculator will save time on test day.

4 Working with Linear Graphs
When a linear equation in written in slope-intercept form (y= mx+b), the variable m gives the slope of the line & b represents the point at which the line intersects the y-axis In a real-world scenario, slope represents a unit rate and the y-intercept represents a starting amount The rate of change (slope) for a linear relationship is constant (DOES NOT VARY) Slope is given by the formula m = y2 - y1/ x2 - x1 (X1, y1) & (x2, y2) are coordinates of points on the line *Remember RISE OVER RUN

5 Working with Linear Graphs cont.
A line with a positive slope runs up and to the right (“uphill”) A line with a negative slope runs down and to the right (“downhill”) A horizontal line has a slope of 0 (with NO rise to left or right!) A vertical line has an undefined slope Parallel lines have the same slope Perpendicular lines have negative reciprocal slopes (ex: 3 and -⅓) *To find a graph that matches a given equation (& vice versa), find the slope (m) of the line and its y-intercept (b).

6 SLOPE = RATE

7 x= independent variable
y= dependent variable “Infinite # of solutions” = solve for the variable

8 Practice 1 3y + 2(y-2) = -25 What value of y satisfies the equation above? -29/5 -21/5 21/5 29/5

9 Practice 1 answer 3y + 2(y-2) = -25
What value of y satisfies the equation above? -29/5 -21/5 21/5 29/5

10 Reasoning Start by distributing the 2. Then collect like terms until you isolate y. 3y + 2(y-2) = -25 3y + 2y - 4 = -25 5y - 4 = -25 Y = -21/5

11 Let’s continue in your books!
Open to page 40 and complete questions 1-??? of the “extra practice problems.” We will check them tomorrow.


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