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Solving Systems using Substitution
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Substitution β Replacing Evaluate one equation for one variable
Example: π¦=3π₯+7 Substitute the resulting expression for the variable in the second equation.
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Steps to Solving a Sd Kf
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Solve the system by using substitution: y = 4x β 1 2x + 2y = 3
Because y = 4x β 1, substitute 4x β 1 for y in 2x + 2y = 3. 2x + 2y = 3 ο Write the second equation 2x + 2(4x β 1) = 3 ο Substitute 4x β 1 for y 2x + 8x β 2 = 3 ο Use the Distributive Property 10x β 2 = 3 ο Simplify 10x = 5 ο Add 2 to each side x = Β½ ο Divide each side by 10 Substitute Β½ for x in either equation and solve for y. y = 4x β 1 y = 4(Β½) β 1 y = 2 β 1 y = 1 The solution of the system is (Β½, 1)
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Solve the system by using substitution: -9x + 5y = -1 -3x + y = 4
The solution of the system is (-3.5, -6.5)
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Solve the system by using substitution: -2x + y = 3 3x β 2y = 0
The solution of the system is (-6, -9)
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