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AP Physics L08_resistivity and resistivity
Resistance and resistivity
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Current Current is sort of a vector
Direction is constrained by conductor Restricted to forward or backward (+ or –)
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Resistance Current does not flow unhindered
Electrical resistance is analogous to friction or drag Expressed as potential needed to maintain a current
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AP Physics L08_resistivity
Ohm’s Law I = DV R I = current DV = voltage = electric potential drop R = resistance Good conductors have low resistance. Unit of resistance : V / A = ohm (W) 4
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Voltage Causes Current
Potential drop is the cause. Current is the effect. Resistance reduces the effect of potential.
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Does it Work? Approximation of varying utility: R is independent of DV and I When true, the material is ohmic
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Circuit symbol zigzag straight line is a perfect conductor
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Poll Question If you want to increase the current through a resistor, you need to Increase the resistance or voltage. Decrease the resistance or voltage. Increase the resistance or decrease the voltage. Decrease the resistance or increase the voltage.
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AP Physics L08_resistivity
Ohm’s Law Rearranged If you know two, you can find the third. DV DV I = DV = IR R = R I Good conductors have low resistance. I = current DV = potential R = resistance
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Example A 1.5-V battery powers a light bulb with a resistance of 9 W. What is the current through the bulb? Ohm’s Law I = V / R V = 1.5 V; R = 9 W I = (1.5 V ) / (9 V/A) = 1/6 A
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Resistivity For current through a cylinder: Longer L greater R.
Greater A smaller R. More resistive material bigger R.
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Resistivity R = r L/A r is Resistivity Unit: ohm·meter = Wm
More or less constant depending on material, conditions
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Resistivity Intensive quantity
Does not depend on the amount of material, only its conditions Predictive value when mostly constant (ohmic)
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Resistivities vary widely
Silver 1.59 10–8 Wm Graphite 3.5 105 Wm Quartz 75 1016 Wm
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Example The resistivity of copper is 1.710–8 Wm. What is the resistance of a 100-km length of copper wire that is 1/4” in diameter?
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Classes of Conductors How resistivity changes with temperature
a = temperature coefficient of resistivity
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Classes of Conductors How resistivity changes with temperature
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dissipated by a resistor
Power dissipated by a resistor
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AP Physics L08_resistivity
Electric Power Potential is energy per charge: V = DE / q Current is charge per time: I = q /Dt So, (potential times current) = (energy per time) = power Good conductors have low resistance. Power = VI
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Group Work Power P = VI and V = IR. Using these, show that: P = I2R
P = V2/R
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