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Ch. 2: Fundamental of Structure
Aircraft is a structure Structures provide aerodynamic properties Challenge: weight must minimum Structural strength vs weight Solid Mechanics How a solid object resists/supports load ? Solid ? Conservations ?
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Elasticity Ability to bounce back Aircraft has limited elasticity
Stress & Strain
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Elasticity
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Stress Strain Measure of force intensity = F/A Units !!
Five Types Of Stress Tension Compression Bending force Torsion Shear force Strain Measure of deformation Units ? = /L
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Stress & Strain Measure of force intensity
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Example 2.1 A prismatic bar with rectangular cross section (20mmx40mm)
and length, L=2.8m is subjected to an axial tensile force 70 kN. The measured elongation of the bar is =1.2mm. Calculate the tensile stress and strain in the bar.
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Sign Conventions/Notation of Stresses
Stress at a point (A) on a plane of a body has the components of; 1 direct stress, 2 shear stresses, x : direct stress in the direction of x axis xy : shear stress x: the plane, y: the direction On each plane, there are 2 equal; but opposite stresses In the x axis direction; +ve & tensile In the –ve x axis direction; -ve & compression
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State of Equilibrium Stresses on opposites faces are differ & stated in Taylor’s series;
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State of Equilibrium Stresses on opposites faces are differ & stated in Taylor’s series; X, Y, Z are force per unit area.
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Plane Stress Aircraft structural components thin metal sheet
Stress across thickness negligible
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Stresses on Inclined Plane
The chosen of axes system is arbitrary So need to examine stresses on other planes
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Stresses on Inclined Plane
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Example 2.2 A cylindrical pressure vessel has an internal diameter of 2m and is fabricated from 20mm thick plate. The pressure inside the vessel is 1.5N/mm2, and the vessel is also subjected to axial tensile load of 2500kN. Determine the direct and shear stresses on a plane inclined at an angle of 60o to the axis of the vessel. Determine also the maximum shear stress.
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Example 2.3 A cantilever solid beam, circular cross section supports a compressive load of 50kN applied to its free end at a point 1.5m below a horizontal diameter in the vertical plane of symmetry together with a torque of 1200Nm. Calculate the direct and shear stresses on a plane inclined at 60o to the axis of the cantilever at a point on the lower edge of the vertical plane of symmetry. Sixma bending=My/I. I is 2nd moment of area, for circle=pai *d^4/64
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Stop 20/09/2012
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Principles Stress : direct (normal)
The stress on the inclined plane is max/min when Differentiate n w.r.t , 2 solutions at and +/2 Principal stress (max) Sixma bending=My/I. I is 2nd moment of area, for circle=pai *d^4/64 Principal stress (min)
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Principles Stress : shear
The stress on the inclined plane is max/min when Differentiate w.r.t , 2 solutions at and +/2 The plane of max shear stress at 45o to principal plane Principal stress (max) Sixma bending=My/I. I is 2nd moment of area, for circle=pai *d^4/64 Principal stress (min)
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Stress on Mohr’s Circle
Stress on inclined plane; Sixma bending=My/I. I is 2nd moment of area, for circle=pai *d^4/64
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Strain Force causes the body to deform : strain
Direct strain : due to direct stress Shear strain: due to shear stress Points P & Q deformed to P’ & Q’ the normal strain are,
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Shear Strain Shear strain components are;
Rigid body motion ; a body undergoes displacement without inducing strains.
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Example 2.3 Consider a 2-D body (a unit square ABCD) in xy plane. After deformation, four corners points move to A’, B’, C’ and D’ respectively. Assume the displacement in the x and y direction are given by u=0.01y and v=0.015x respectively. Obtain the deformed coordinates, normal strain and shear strain.
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Principal Strain The principal strains are given by,
The principal strains can be determined graphically by using Mohr’s circle for strain
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Stress-Strain Relation
6 components stress; 6 components strains; For plane stress, we have E is Young’s modulus is Poisson’s ratio G is modulus of rigidity
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Stress-Strain : Example 2.4
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Stress-Strain : Example 2.5
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