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Review Applications of Database Systems

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1 Review Applications of Database Systems
Theory Applications of Database Systems Practice

2 ER-diagram Relational databases: Theory Part Referential integrity Relation normalization

3 ER-diagram Entity types Strong entity type Weak entity type Attributes atomic attributes composite attributes single-valued attributes multi-valued attributes Relationships Cardinality constraints Participation constraints Identifying relationship, recursive relationship

4 Mapping from ER-diagrams onto relational schemas
Create a relation for each strong entity type Create a relation for each weak entity type 3. For each binary 1:1 relationship choose an entity and include the other’s PK in it as an FK 4. For each binary 1:n relationship, choose the n-side entity and include an FK with respect to the other entity. 5. For each binary M:N relationship, create a relation for the relationship 6. For each multi-valued attribute create a new relation 7. For each n-ary relationship, create a relation for the relationship

5 Referential Integrity
(i) Consider two relation schemas R1 and R2; The attributes in FK (foreign key) in R1 have the same domain(s) as the primary key attributes PK (primary key) in R2; the attributes FK are said to reference or refer to the relation R2. iii) A value of FK in a tuple (record) t1 of the current state r(R1) either occurs as a value of PK for some tuple t2 in the current state r(R2) or is null. In the former case, we have t1[FK] = t2[PK], and we say that the tuple t1 references or refers to the tuple t2. Example: FK Employee(SSN, …, Dno) Dept(Dno, … )

6 Relationships Window ConsultantID is primary key in Consultant table
Relationship line ConsultantID is foreign key in Clients table

7 You cannot delete a Consultant without first deleting related Clients
Delete Record button Click + to display related records You cannot delete a Consultant without first deleting related Clients

8 fname, minit, lname, ssn, bdate, address, sex, salary, superssn, dno
Dname, dnumber, mgrssn, mgrstartdate Dnumber, dlocation Pname, pnumber, plocation, dnum Essn, pno, hours Essn, dependentname, sex, bdate, relationship EMPLOYEE DEPARTMENT DEPT _LOCATIONS WORKS_ON PROJECT DEPENDENT

9 Updating and constraints
delete Delete the WORK_ON tuple with Essn = ‘ ’ and pno = 10. When deleting, the referential constraint will be checked. - The following deletion is not acceptable: Delete the EMPLOYEE tuple with ssn = ‘ ’ - reject, cascade, modify

10 Cascade deletion – a strategy to enforce referential integrity
Employee ssn ... delete Works-on Essn Pno 5 ... delete

11 cascade – a strategy to enforce referential integrity
Employee delete ssn supervisor null Employee ssn supervisor null not reasonable delete delete

12 This violates the entity constraint. Works-on
Modify (cascade updating) – a strategy to enforce referential integrity ssn ... Employee Essn Pno 5 delete null This violates the entity constraint. Works-on

13 Modify (cascade updating) – a strategy to enforce referential
integrity Employee ssn ... delete Department Dno ... 5 chairman Department null Dno ... 5 chairman This does not violate the entity constraint.

14 Normalization We discuss four normal forms: first, second, third, and Boyce-Codd normal forms 1NF, 2NF, 3NF, and BCNF Normalization is a process that “improves” a database design by generating relations that are of higher normal forms. The objective of normalization: “to create relations where every dependency is on the key, the whole key, and nothing but the key”.

15 Functional Dependencies
We say an attribute, B, has a functional dependency on another attribute, A, if for any two records, which have the same value for A, then the values for B in these two records must be the same. We illustrate this as: A  B Example: Suppose we keep track of employee addresses, and we only track one address for each employee . Suppose each employee is identified by their unique employee number. We say there is a functional dependency of address on employee number: employee number  address

16 If EmpNum is the PK then the FDs: EmpNum  EmpEmail EmpNum  EmpFname
EmpLname 123 John Doe 456 Peter Smith 555 Alan Lee 633 Peter Doe 787 Alan Lee If EmpNum is the PK then the FDs: EmpNum  Emp EmpNum  EmpFname EmpNum  EmpLname must exist.

17 Transitive dependency
Consider attributes A, B, and C, and where A  B and B  C. Functional dependencies are transitive, which means that we also have the functional dependency A  C We say that C is transitively dependent on A through B.

18 EmpNum  DeptNum EmpNum Emp DeptNum DeptNname DeptNum  DeptName EmpNum Emp DeptNum DeptNname DeptName is transitively dependent on EmpNum via DeptNum EmpNum  DeptName

19 A partial dependency exists when an attribute B is functionally dependent on an attribute A, and A is a component of a multipart candidate key. InvNum LineNum Qty InvDate Candidate keys: {InvNum, LineNum} InvDate is partially dependent on {InvNum, LineNum} as InvNum is a determinant of InvDate and InvNum is part of a candidate key

20 First Normal Form We say a relation is in 1NF if all values stored in the relation are single-valued and atomic. 1NF places restrictions on the structure of relations. Values must be simple.

21 Boyce-Codd Normal Form BCNF is defined very simply:
a relation is in BCNF if it is in 1NF and if every determinant is a candidate key. InvNum LineNum ProdNum Qty InvNum, LineNum ProdNum {InvNum, LineNum} and {InvNum, ProdNum} are the two candidate keys. Qty InvNum, ProdNum LineNum

22 Second Normal Form A relation is in 2NF if it is in 1NF, and every non-key attribute is fully dependent on each candidate key. 2NF (and 3NF) both involve the concepts of key and non-key attributes. A key attribute is any attribute that is part of a key; any attribute that is not a key attribute, is a non-key attribute. Relations that are not in BCNF have data redundancies A relation in 2NF will not have any partial dependencies

23 Consider this InvLine table (in 1NF):
InvNum LineNum ProdNum Qty InvDate InvNum, LineNum ProdNum There are two candidate keys. Qty InvNum, ProdNum LineNum Qty is the only non-key attribute, and it is dependent on InvNum InvNum InvDate Since there is a determinant that is not a candidate key, InvLine is not BCNF InvLine is not 2NF since there is a partial dependency of InvDate on InvNum InvLine is only in 1NF

24 InvNum LineNum ProdNum Qty InvNum InvDate inv_no line_no prod_no prod_desc qty EmployeeDept ename ssn bdate address dnumber dname

25 Third Normal Form a relation is in 3NF if the relation is in 1NF and all determinants of non-key attributes are candidate keys That is, for any functional dependency: X  Y, where Y is a non-key attribute (or a set of non-key attributes), X is a candidate key. this definition of 3NF differs from BCNF only in the specification of non-key attributes - 3NF is weaker than BCNF. (BCNF requires all determinants to be candidate keys.) A relation in 3NF will not have any transitive dependencies

26 EmpNum EmpName DeptNum DeptName We correct the situation by decomposing the original relation into two 3NF relations. Note the decomposition is lossless.

27 {student_no, course_no}  instr_no instr_no  course_no
Instructor teaches one course only. Student takes a course and has one instructor. In 3NF, but not in BCNF: {student_no, course_no}  instr_no instr_no  course_no since we have instr_no  course-no, but instr_no is not a Candidate key.

28 course_no instr_no student_no BCNF {student_no, instr_no}  student_no {student_no, instr_no}  instr_no instr_no  course_no

29 Tables Forms Reports Practice Part Queries Macros not covered VBA modules

30 Tables - table name - attribute name - attribute data type - attribute properties - Primary key - Foreign key

31

32 Data Types of Fields Attachment    Files, such as digital photos. Multiple files can be attached per record. This data type is not available in earlier versions of Access. AutoNumber    Numbers that are automatically generated for each record. Currency    Monetary values. Date/Time    Dates and times. Hyperlink    Hyperlinks, such as URL addresses. Memo    Long blocks of text and text that use text formatting. A typical use of a Memo field would be a detailed product description. Number    Numeric values, such as distances. Note that there is a separate data type for currency. OLE Object    OLE objects (OLE object: An object supporting the OLE protocol for object linking and embedding. Text    Short, alphanumeric values, such as a last name or a street address. Yes/No    Boolean values.

33 Properties Field size- Adjusts the size of the text field
Format- changes the way field is displayed. Does not effect the value. Input Mask- facilitates data entry Caption- Label used for the field Default Value- the automatically entered value Validation Rule- Rejects records that do not conform to rules entered. Validation Text- Error returned when validation rule is broken. Required- Forces user to enter in value if selected. Allow Zero Length- Allows text length of 0. Indexed- increases efficiency of search on the field

34 Examples for Format property
Format property for Number data type: #,###.##;(#,###.##)[Red];0,000.00;“Undefined” format for positive number format for 0 format for null-value format for negative number 6,789.77

35 Examples for Input Mask property
Input mask for Text data type: !\(999") "000\-0000;0;_ e.g. (204) >!“FJ”-AA\ e.g. FJ-EA-12048 Input mask for Time data type 99:00:00\ >LL;0;_ e.g. 05:56:00 PM

36 Forms different components: - bound controls - unbound controls - calculated controls - drop-down list box (combo box) - check box - option group - command buttons

37

38

39 Subforms

40 Subforms are generated using Wizard

41 Subsubforms

42 Subforms are generated using Subform/Subreport button

43 Switchboard is a special form created using Switchboard
manager (not covered)

44

45 Reports seven sections: - report header - page header - group header - details - group footer - page footer - report footer

46

47

48 Queries different kinds of queries: - select queries - action queries Make-Table query, Delete-Table query Append-Table query, Update query parameter query, unmatched query, find-duplicates query - Crosstab query - total queries Group by Aggregate functions: Count, sum, maximum, minimum, Average

49 Queries - unmatched queries

50

51 Query design grid

52 SQL statement Select FirstName, LastName From Employees Where Salary > 40000

53 Structured Query Language
SELECT Orders.CustomerID, Orders.EmployeeID, Orders.OrderDate, Orders.Freight FROM Orders WHERE (((Orders.OrderDate)>#3/25/2010#)) OR (((Orders.EmployeeID)<7));

54 Structured Query Language
SELECT Orders.CustomerID, Orders.EmployeeID, Orders.OrderDate, Orders.Freight, [Order Details].Quantity FROM Orders INNER JOIN [Order Details] ON Orders.OrderID = [Order Details].OrderID WHERE (((Orders.OrderDate)>#3/25/2010#) AND (([Order Details].Quantity)>7)) OR (((Orders.EmployeeID)<7));

55 Relationships a many-to-many relationship is created by generating two one-to-many relationships.

56 Macros

57 Macro groups

58 VBA modules

59 Private Sub cmdHistoryForm_Click()
'Display the form DoCmd.OpenForm("Employee"), , , , acFormEdit End Sub Private Sub cmdEmployeeForm_Click() DoCmd.OpenForm("History"), , , , acReadOnly Private Sub cmdExit_Click() 'Exit the application intResponse = MsgBox("Do you want to exit the Compensation" & _ "application?", vbYesNo + vbCritical, "Exit Application?") If intResponse = vbYes Then Application.Quit acQuitPrompt End If

60 Private Sub cmdSummaryReport_Click()
'This procedure defines an SQL query as the record source 'for the "Retirement Summary" report; the SQL statement 'returns all records 'Assign the report name to the strObjectName variable strObjectName = "Retirement Summary" 'Declare a variable to store the SQL statement, define the 'SQL string strSQL = "SELECT Employee.LastName, Employee.FirstName, " & _ "Office.Region, Contribution.PayDate," & _ "Contribution.[401KEmployee], " & _ "Contribution.[401KMatch], Contribution.[401KTotal], " & _ "FROM (Office INNER JOIN Employee ON Office.[OfficeNumber] = " & _ "Employee.[OfficeLocation])" & _ "INNER JOIN Contribution ON Employee.[SSN] = Contribution.[SSN];"


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