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Reconstruction on trees and Phylogeny 4
Elchanan Mossel, U.C. Berkeley Supported by Microsoft Research and the Miller Institute 11/22/2018
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Future research in Phylogeny
Applications: Check validity of currently published phylogenies. See if new reconstruction methods out-perform existing ones. See if standard methods (e.g. Maximum likelihood) behave differently in different phases. CFN and R.C models Prove logarithmic reconstruction under “average” low mutation. Try and remove clock/balance condition for CFN model. Other Markov modes on trees. Prove logarithmic reconstruction for low mutation rate. Critical value? 11/22/2018
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Future research in Phylogeny
Network tomography. Check how methods do for recovering tree-networks. Other tree models (e.g. coming from delays). Other graphical models. Is phase transition playing a similar role in reconstructing tree-like and non-tree-like graphical models? Importance of “phase transition” for other problems in graphical models. 11/22/2018
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Reconstruction for other Markov models
Leaving the Ising model … Reconstruction for other models is more interesting. The “natural” bound for reconstruction is b ||2 > 1, where is the second eigen-value of M (in absolute value). In “count reconstruction” we reconstruct from Yn = (Yn(i))i 2 A, where Y_n(i) = # of times color i appears at the n’th level. Theorem [M-Peres 2002]: The count reconstruction problem is solvable if b ||2 > 1 and unsolvable if b ||2 < 1. 11/22/2018
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Reconstruction for other Markov models
Theorem [M-Peres 2002]: The count reconstruction problem is solvable if b ||2 > 1 and unsolvable if b ||2 < 1. Proof uses [Kesten-Stigum-66] theorem. 11/22/2018
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Robust Reconstruction for Markov models
So the threshold b 2 = 1 is important. But [M-2000] it is not the threshold for the reconstruction problem. Not even for 2 £ 2 markov chains, Or symmetric markov chains on q symbols. Moreover, there exists a markov chain M s.t. = 0, but the reconstruction problem is solvable for some b. 11/22/2018
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Reconstruction for Markov models
In “robust reconstruction”, instead of the n’th level, n, we are given n, where for each v at level n n(v) = n(v) with probability , n(v) = an independent color from a distribution with probability 1 - . Similar to “robust phase transition” Pemantle-Steif 99. Easy: if b 2 > 1 then robust reconstruction is solvable for all > 0. Theorem [Janson-M 2003]: If b 2 < 1, then for > 0 small, robust reconstruction is unsolvable. Same is true with br(T) instead of b. 11/22/2018
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