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Generalized Network Flow (GNF) Problem

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1 Generalized Network Flow (GNF) Problem
Each arc (i, j) has a multiplier ij If 1 unit of flow leaves node i on arc (i, j), then ij will arrive node j. When ij< 1 the arc is said to be lossy. When ij> 1 the arc is said to be gainy. cij, ij and uij apply to the amount of flow leaving node i. Generalized Network Flow

2 LP Formulation of GNFP Note: the flows are usually not integral
in GNFP Generalized Network Flow

3 GNFP Example: Paper Recycling Problem
Three types of paper plus fresh wood Minimize use of fresh wood subject to: Generalized Network Flow

4 Formulation as GNFP: Transportation Subproblem
ij = 0.85 ij =0.80 1a 1b ij =0.90 2a 2b F cij=1 3a 3b Generalized Network Flow

5 Formulation as GNFP: Supplies and Demands
1b -3475 4000 2a 2b F 1600 -1223 ? 3a 3b 1000 -2260 Generalized Network Flow

6 Supply of Fresh Wood Add arc (F, F) with multiplier FF .
Flow Out = xF1b + xF2b + xF3b + xFF Flow In = FF xFF Out – In = xF1b + xF2b + xF3b + (1- FF) xFF Let bF = 0 and FF = 2. 0 = xF1b + xF2b + xF3b + (-1) xFF xFF= xF1b + xF2b + xF3b Generalized Network Flow

7 Supply of Wood Type 1 Add arc (1a, 1a) with multiplier 1a1a.
Flow Out = x1a1a + x1a1b + x1a2b Flow In = 1a1a x1a1a Out – In = x1a1b + x1a2b + (1- 1a1a) x1a1a Let b1a = 4000 and 1a1a = 0.5. x1a1b + x1a2b + (0.5) x1a1a= 4000 Unused supply of wood type 1 = x1a1a Generalized Network Flow

8 Formulation as GNFP: Slack Arcs
 = 0.5 1a 1b  = 2 2a 2b F  = 0.5 3a 3b  = 0.5 Generalized Network Flow


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