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Lectures prepared by: Elchanan Mossel Yelena Shvets

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1 Lectures prepared by: Elchanan Mossel Yelena Shvets
Introduction to probability Stat FAll 2005 Berkeley Lectures prepared by: Elchanan Mossel Yelena Shvets Follows Jim Pitman’s book: Probability Section 2.1

2 Binomial Distribution
Toss a coin 100, what’s the chance of ? hidden assumptions: n-independence; probabilities are fixed.

3 Magic Hat: Each time we pull an item out of the hat it magically reappears. What’s the chance of drawing 3 I-pods in 10 trials? ={ }

4 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=0

5 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=1

6 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=2

7 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=3

8 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=4

9 Binomial Distribution
Suppose we roll a die 4 times. What’s the chance of k ? Let ={ } Binomial Distribution k=0 k=1 k=2 k=3 k=4

10 Binomial Distribution
How do we count the number of sequences of length 4 with 3 . and 1 .? .1 1. ..1 .2. 1.. ...1 ..3. .3.. 1... ....1 ...4. ..6.. .4... 1....

11 Binomial Distribution
This is the Pascal’s triangle, which gives, as you may recall the binomial coefficients.

12 Binomial Distribution
2ab 1b2 1a3 3a2b 3ab2 1b3 1a4 4a3b 6a2b2 4ab3 1b4 (a + b) = (a + b)2 = (a + b)3 = (a + b)4 =

13 Newton’s Binomial Theorem

14 Binomial Distribution
For n independent trials each with probability p of success and (1-p) of failure we have This defines the binomial(n,p) distribution over the set of n+1 integers {0,1,…,n}.

15 Binomial Distribution
This represents the chance that in n draws there was some number of successes between zero and n.

16 Example: A pair of coins
A pair of coins will be tossed 5 times. Find the probability of getting on k of the tosses, k = 0 to 5. binomial(5,1/4)

17 Example: A pair of coins
A pair of coins will be tossed 5 times. Find the probability of getting on k of the tosses, k = 0 to 5. # =k To fill out the distribution table we could compute 6 quantities for k = 0,1,…5 separately, or use a trick.

18 Binomial Distribution: consecutive odds ratio
Consecutive odds ratio relates P(k) and P(k-1).

19 Example: A pair of coins
Use consecutive odds ratio to quickly fill out the distribution table Example: A pair of coins for binomial(5,1/4): k 1 2 3 4 5

20 Binomial Distribution
We can use this table to find the following conditional probability: P(at least | at least in first 2 tosses) = P(3 or more & 1 or in first 2 tosses) P(1 or in first 2)

21 bin(5,1/4): k 1 2 3 4 5 bin(2,1/4): k 1 2

22 Stirling’s formula How useful is the binomial formula? Try using your calculators to compute P(500 H in 1000 coin tosses) directly: My calculator gave me en error when I tried computing 1000!. This number is just too big to be stored.

23 The following is called the Stirling’s approximation.
It is not very useful if applied directly : nn is a very big number if n is 1000.

24 Stirling’s formula:

25 Binomial Distribution
Toss coin 1000 times; P(500 in 1000|250 in first 500)= P(500 in 1000 & 250 in first 500)/P(250 in first 500)= P(250 in first 500 & 250 in second 500)/P(250 in first 500)= P(250 in first 500) P(250 in second 500)/ P(250 in first 500)= P(250 in second 500)=

26 Binomial Distribution: Mean
Question: For a fair coin with p = ½, what do we expect in 100 tosses?

27 Binomial Distribution: Mean
Recall the frequency interpretation: p ¼ #H/#Trials So we expect about 50 H !

28 Binomial Distribution: Mean
Expected value or Mean (m) of a binomial(n,p) distribution m = #Trials £ P(success) = n p slip !!

29 Binomial Distribution: Mode
Question: What is the most likely number of successes? Mean seems a good guess.

30 Binomial Distribution: Mode
Recall that To see whether this is the most likely number of successes we need to compare this to P(k in 100) for every other k.

31 Binomial Distribution: Mode
The most likely number of successes is called the mode of a binomial distribution.

32 Binomial Distribution: Mode
If we can show that for some m P(1) · … P(m-1) · P(m) ¸ P(m+1) … ¸ P(n), then m would be the mode.

33 Binomial Distribution: Mode
so we can use successive odds ratio: to determine the mode.

34 Binomial Distribution: Mode
successive odds ratio: > If we replace · with > the implications will still hold. So for m=bnp+pc we get that P(m-1) · P(m) > P(m+1).

35 Binomial Distribution: Mode - graph SOR
k

36 Binomial Distribution: Mode - graph distr
k mode = 50

37 Lectures prepared by: Elchanan Mossel Yelena Shvets
Introduction to probability Stat FAll 2005 Berkeley Lectures prepared by: Elchanan Mossel Yelena Shvets Follows Jim Pitman’s book: Probability Section 2.1


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