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energy = cm∆t = J = c = 1.2  105 J J/kg • K 25 K 0.34kg

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Presentation on theme: "energy = cm∆t = J = c = 1.2  105 J J/kg • K 25 K 0.34kg"— Presentation transcript:

1 energy = cm∆t = 121550 J = c = 1.2  105 J 14300 J/kg • K 25 K 0.34kg
1. The element hydrogen has the highest specific heat of all elements. At a temperature of 25°C, hydrogen’s specific heat is 1.43  104 J/kg • K. If the temperature of a 0.34 kg sample of hydrogen is to be raised by 25 K, how much energy will have to be added to the hydrogen? 14300 J/kg • K 25 K 0.34kg X X ∆t = 25 K J m = 0.34kg c = 1.43  104 J/kg • K 1.2  105 J

2 2. The element radon is at the opposite end of the range with the lowest specific heat of all naturally occurring elements. At 25°C, radon’s specific heat is 94 J/kg • K. If the temperature of a 0.34 kg sample of radon is to be raised by 25 K, how much energy will have to be added to the radon? 94 J/kg • K X 0.34 kg 25K X 799 J


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