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Mathematical Induction
Divisibility
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = f(2) = f(3) = f(4) =
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = f(2) = f(3) = f(4) =
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80 f(2) = 6560
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80 f(2) = 6560 f(3) =
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80 f(2) = 6560 f(3) = f(4) =
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80 f(2) = 6560 f(3) = f(4) = Now take a guess and make up a theory. What is the highest common factor of your answers……?
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Review A function is defined for integers only such that f(n) = 34n -1. Find; f(1) = 80 f(2) = 6560 f(3) = f(4) = Now take a guess and make up a theory. What is the highest common factor of your answers……?
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Did you get 80? f(1) = 80 = 80 1 f(2) = 6560 = 80 82 f(3) = = 80 6643 f(4) = = 80 53804 And this is an important idea. If a number is divisible by 80 then we can write it as 80 M where M is a positive integer.
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Did you get 80? f(1) = 80 = 80 1 f(2) = 6560 = 80 82 f(3) = = 80 6643 f(4) = = 80 53804 And this is an important idea. If a number is divisible by 80 then we can write it as 80 M where M is a positive integer.
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So now the theory is that any number of the form 34n -1 where n is a positive integer is divisible by 80.
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So now the theory is that any number of the form 34n -1 where n is a positive integer is divisible by 80. So how would we prove it?
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So now the theory is that any number of the form 34n -1 where n is a positive integer is divisible by 80. So how would we prove it? MATHEMATICAL INDUCTION !
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1. Prove that any number of the form 34n -1
1. Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction.
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction.
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 1 : Prove true for n = 1. 34 1 -1 = 80 = 80 1 which is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 1 : Prove true for n = 1. 34 1 -1 = 80 = 80 1 which is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 2 : Assume true for n = k. 34 k -1 = 80 M where M is a positive integer
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 2 : Assume true for n = k. 34 k -1 = 80 M where M is a positive integer 34 k = 80 M + 1 note that it is very important to make 34 k the subject
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 2 : Assume true for n = k. 34k -1 = 80 M where M is a positive integer 34k = 80 M + 1 note that it is very important to make 34k the subject
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 2 : Assume true for n = k. 34k -1 = 80 M where M is a positive integer 34k = 80 M + 1 note that it is very important to make 34k the subject
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Prove that any number of the form 34n -1
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80
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Step 3 : Prove true for n = k + 1.
Prove that any number of the form 34n -1 where n is a positive integer is divisible by 80, using mathematical induction. Step 3 : Prove true for n = k + 1. RTP that 34(k + 1) -1 is divisible by 80 proved by induction
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction.
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction.
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 1 : Prove true for n = 1.
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 1 : Prove true for n = 1.
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 1 : Prove true for n = 1. = 10 = 2 5 , true for n = 1
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 2 : Assume true for n = k, (k is odd).
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 2 : Assume true for n = k, (k is odd). 3k + 7k = 5 M
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 2 : Assume true for n = k, (k is odd). 3k + 7k = 5 M 7k = 5 M - 3k
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 2 : Assume true for n = k, (k is odd). 3k + 7k = 5 M 7k = 5 M - 3k note that it is important to make one of them the subject and it is easier to use the bigger number.
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Prove that any number of the form 3n + 7n
Prove that any number of the form 3n + 7n where n is an odd integer is divisible by 5, using mathematical induction. Step 3 : Prove true for n = k + 2. RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5 So it is true for n = k + 2, proved by induction
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Step 3 : Prove true for n = k + 2.
RTP 3k k + 2 is divisible by 5 So it is true for n = k + 2, proved by induction
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