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Prototype 2nd order system:
target
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Type 1: Settling time: = (3 or 4 or 5)/s For 5%, 2%, 1% tol
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Pole location determines transient
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All closed-loop poles must be strictly in the left half planes
Transient dies away Dominant poles: those which contribute the most to the transient Typically have dominant pole pair (complex conjugate) Closest to jω-axis (i.e. the least negative) Slowest to die away
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Typical design specifications
Steady-state: ess to step ≤ # % ts ≤ · · · Speed (responsiveness) tr ≤ · · · td ≤ · · · Relative stability Mp ≤ · · · %
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These specs translate into requirements
on ζ, ωn or on closed-loop pole location : Find ranges for ζ and ωn so that all 3 are satisfied.
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Find conditions on σ and ωd.
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In the complex plane : Any pole on the ray have the same z p=-s + jwd
Mp < … or z > … corresponds to a conic region about the neg real axis j -s
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Constant σ : vertical lines σ > # is half plane
Any poles on the same vertical line have the same s, and the same settling time ts s=1 or ts=5 s>2 or ts=2.5 ts < … corresponds to a half plane to the left of a vertical line
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Constant ωd : horizontal line ωd < · · · is a band
ωd > · · · is the plane excluding band Any poles on the same horizontal line have the same wd, and the same oscillation frequency A centered horizontal band corresponds to oscillation frequency < … The plane excluding a centered horizontal band corresponds to oscillation frequency > …
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ωn < · · · inside of a circle ωn > · · · outside of a circle
Constant ωn : circles ωn < · · · inside of a circle ωn > · · · outside of a circle Any poles on the same circle have the same wn, and similar rise time/delay time Inside circle corresponds to tr> … Outside a circle corresponds to tr < …
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Constant ζ : φ = cos-1ζ constant
Constant ζ = ray from the origin ζ > · · · is the cone ζ < · · · is the other part
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If more than one requirement, get the common (overlapped) area
e.g. ζ > 0.5, σ > 2, ωn > 3 gives Sometimes meeting two will also meet the third, but not always.
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Try to remember these:
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When given unit step input, the output looks like:
Example: + - When given unit step input, the output looks like: Q: estimate k and τ.
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When given unit step input, the output looks like:
Example: + - When given unit step input, the output looks like: Q: estimate k and τ. Yss = ____; is it prototype? Mp = ____; tp = ____; 5% ts = ____
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Solve for J and t
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Effects of additional zeros
Suppose we originally have: i.e. step response Now introduce a zero at s = -z The new step response:
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Effects: Increased speed, Larger overshoot, Might increase ts
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When z < 0, the zero s = -z is > 0,
is in the right half plane. Such a zero is called a nonminimum phase zero. A system with nonminimum phase zeros is called a nonminimum phase system. Nonminimum phase zero should be avoided in design. i.e. Do not introduce such a zero in your controller.
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Effects of additional pole
Suppose, instead of a zero, we introduce a pole at s = -p, i.e.
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L.P.F. has smoothing effect, or
averaging effect Effects: Slower, Reduced overshoot, May increase or decrease ts
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